Answer:
0.40
Step-by-step explanation:
The percentage of members who engage only in long-distance running is 8%
Therefore, the probability that a member focuses solely on long-distance running is P(A) = 0.08
The percentage of members who participate exclusively in field events is 32%
Thus, the probability of a member competing only in field events is P(B) = 0.32
The percentage of members acting as sprinters is 12%
So, the probability that a member is a sprinter is P(C) = 0.12
We need to determine the probability that a team member is either an exclusive long-distance runner or an only field event competitor, which equates to finding P(A or B). Since these two events cannot occur simultaneously, we can express this as:
P(A or B) = P(A) + P(B)
Substituting the known values results in:
P(A or B) = 0.08 + 0.32 = 0.40
Thus, the likelihood that a randomly selected team member runs exclusively long-distance or participates solely in field events stands at 0.40
Answer:
24
Step-by-step explanation:
Based on the logarithmic expressions given 
, we need to identify the value of 
By substituting x = a³, y = a⁷, and z = a⁻² into the logarithmic function , we will derive;
Therefore, the result of the logarithmic expression is 24
Response:
Step-by-step breakdown:
For the null hypothesis,
H0: p = 88
For the alternative hypothesis,
Ha: p < 88
In terms of population proportion, where the probability of success is p = 0.88
q represents the probability of failure = 1 - p
q = 1 - 0.88 = 0.12
Considering the sample,
Sample proportion, P = x/n
Where
x = number of successes = 21
n = total samples = 32
P = 21/32 = 0.66
Next, we determine the test statistic, which represents the z-score
z = (P - p)/√pq/n
z = (0.66 - 0.88)/√(0.88 × 0.12)/32 = - 3.83
The relevant p-value corresponds by referencing the normal distribution table for the area falling beneath the z-score. As a result,
P value = 0.00006
