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evablogger
1 month ago
10

A change jar contains nickels dimes and quarters totaling and amount of $1.90 the amount of nickels is one more than twice the n

umber of Dimes the number of quarters is one half the total number of nickels and dimes find the number of each coin in the change jar
Mathematics
2 answers:
Inessa [12.5K]1 month ago
5 0

Nickels - 15
Dimes - 7
Quarters - 2

zzz [12.3K]1 month ago
4 0

Response: Presented below

Explanation step-by-step:

It is known that a nickel is worth 5% of a dollar, a dime corresponds to 10% of a dollar,

and a quarter amounts to 25% of a dollar.

Let x represent the number of dimes.

This implies that hence there are 2x + 1 nickels.

Quarters = \frac{1}{2}(2x+1+x)=\frac{1}{2}(3x+1)

The total value of the coins sums up to $1.90.

x(0.1) + (2x + 1)0.05 + \frac{1}{2}(3x+1)(0.25)=1.9

115x + 35 = 380

x = 3

Thus, the count of nickels = 2 * 3 + 1 = 7.

Quarters = 5

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