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Vaselesa
5 days ago
12

3. An underground copper pipe is used to transport oil under a factory. It is very important that this pipe does not oxidize, so

engineers use impressed current cathodic protection. a. Would zinc be an appropriate metal to use for cathodic protection? Why or why not? (4 points) b. Engineers attach a sacrificial anode to the copper pipe. To use impressed current cathodic protection, they must attach a battery between the cathode and anode. Which material should the positive side of the battery be attached to? Explain how you know. (4 points)
Engineering
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The rigid beam is supported by a pin at C and an A992 steel guy wire AB of length 6 ft. If the wire has a diameter of 0.2 in., d
Mrrafil [318]

Answer:

Change in length = 0.0913 in

Explanation:

Given data:

Length = 6 ft

Diameter = 0.2 in

Load w = 200 lb/ft

Solution:

We start by applying the equilibrium moment about point C, expressed as

∑M(c) = 0.............1

This can be used to find the force in AB.

10× 200 × ( 5) - (T cos(30)) × 10 = 0

Solving gives us

Tension in wire T(AB) = 1154.7 lb

We also know the modulus of elasticity for A992 is

E = 29000 ksi

And the area will be

Area = \frac{\pi }{4}\times 0.2^2

The change in length is expressed as

Change in length = \frac{PL}{AE}.........2

Substituting values results in

Change in length = \frac{1154.7 \times 6 \times 12}{\frac{\pi }{4}\times 0.2^2 \times 29000 \times 1000}

Change in length = 0.0913 in

8 0
3 months ago
Given a 5x5 matrix for Playfair cipher a. How many possible keys does the Playfair cipher have? Ignore the fact that some keys m
alex41 [359]

Answer:

a. 25! = 2^{84}(Approximately)

b. 24!

Explanation:

a. In a Playfair cipher, there are 25 keys available because it is structured in a 5 * 4 grid. By using permutations to enumerate all potential configurations, we derive: 25! = 1.551121004×10²⁵ = 2^{84}

Although there are 26 letters available, in the Playfair cipher, the letters 'i' and 'j' are treated as a single letter.

b. Considering any configuration of 5x5, each of the four row shifts yields equivalent configurations, amounting to five total equivalencies. Similarly, for each of these five setups, any of the four column shifts also results in equivalent arrangements. Therefore, each configuration corresponds to 25 equivalent arrangements. Consequently, the total count of distinct keys can be expressed as:

25!/25 = 24! = 6.204484017×10²³

6 0
1 month ago
How does Accenture generate value for clients through Agile and DevOps?
Daniel [329]
By securing stakeholder needs throughout the project planning stage via thorough process documentation that is revised after each work cycle.
7 0
3 months ago
Read 2 more answers
Which of the following types of protective equipment protects workers who are passing by from stray sparks or metal while anothe
choli [298]

Answer:

Flame-resistant clothing and aprons

Explanation:

Workers involved with welding are generally mandated to wear flame-resistant clothing and aprons to shield them from various hazards, including heat, flames, burns, and potential radiation. In the context of welding, this gear protects individuals from flying sparks that can ignite and cause fires. Hence, such clothing helps to prevent accidents in these situations.

7 0
3 months ago
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