The rigid beam is supported by a pin at C and an A992 steel guy wire AB of length 6 ft. If the wire has a diameter of 0.2 in., d
1 answer:
Answer:
Change in length = 0.0913 in
Explanation:
Given data:
Length = 6 ft
Diameter = 0.2 in
Load w = 200 lb/ft
Solution:
We start by applying the equilibrium moment about point C, expressed as
∑M(c) = 0.............1
This can be used to find the force in AB.
10× 200 × ( 5) - (T cos(30)) × 10 = 0
Solving gives us
Tension in wire T(AB) = 1154.7 lb
We also know the modulus of elasticity for A992 is
E = 29000 ksi
And the area will be
Area =
The change in length is expressed as
Change in length = .........2
Substituting values results in
Change in length =
Change in length = 0.0913 in
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