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9 days ago

Same rule: If both players spend the same number of coins, player 2 gains 1 coin. Off-by-one rule: If the players do not spend t

he same number of coins and the positive difference between the number of coins spent by the two players is 1, player 2 is awarded 1 coin. Off-by-two rule: If the players do not spend the same number of coins and the positive difference between the number of coins spent by the two players is 2, player 1 is awarded 2 coins. The following is an example of a game played with a starting value of 10 coins and a game length of 5 rounds

Engineering

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Steam flows at steady state through a converging, insulated nozzle, 25 cm long and with an inlet diameter of 5 cm. At the nozzle

iogann1982 [368]

Answer:

The velocity at exit U_2 is 578.359 m/s

The exit diameter d_e is 1.4924 cm

Explanation:

Provided data includes:

Length of the nozzle L = 25 cm

Inlet diameter d_i = 5 cm

At the nozzle entrance (state 1): Temperature T_1 = 325 °C, Pressure P_1 = 700 kPa, Velocity U_1 = 30 m/s, Enthalpy H_1 = 3112.5 kJ/kg, Volume V_1 = 388.61 cm³/gAt the nozzle exit (state 2): Temperature T_2 = 250 °C, Pressure P_2 = 350 kPa, Velocity U_2, Enthalpy H_2 = 2945.7 kJ/kg, Volume V_2 = 667.75 cm³/g To determine:a. Exit Velocity U_2b. Exit Diameter d_e

a.The Energy Equation can be represented by:ΔH + ΔU² / 2 + gΔz = Q + WAssuming Q = W = Δz = 0Substituting the values yields:

(H_2 - H_1) + (U²_2 - U²_1) / 2 = 0From which we can derive U_2 = sqrt((2* (H_1 - H_2 )) + U²_1) with the calculations leading to U_2 = sqrt ( 2 * 10^3 * (3112.5 -2945.7) + 900) yielding U_2 = 578.359 m/s

Using mass balance approach, we have U_1 * A_1 / V_1 = U_2 * A_2 / V_2

Here, A = π*d² / 4

This leads to U_1 * d_i² / V_1 = U_2 * d_e² / V_2, thus d_e = d_i * sqrt((U_1 / U_2) * (V_2 / V_1)). Hence, d_e = 5 * sqrt((30 / 578.359) * (667.75 / 388.61)) computes to d_e = 1.4924 cm

6 0

2 months ago

The uniform dresser has a weight of 90 lb and rests on a tile floor for which the coefficient of static friction is 0.25. If the

Kisachek [356]

Answer:

a) $F = 736.065\,lbf$ , b) $\mu_{k} = 0.15$

Explanation:

a) The uniform dresser can be modeled using specific equilibrium equations:

$\Sigma F_{x} = F - \mu_{k}\cdot N = 0$

$\Sigma F_{y} = N-m\cdot g=0$

Following some algebraic manipulations, the formulated equation is derived:

$F = \mu_{k}\cdot m \cdot g$

$F = (0.25)\cdot (90\,lbm)\cdot (32.714\,\frac{ft}{s^{2}} )$

$F = 22.5\,lbf$

b) Similarly, the man can be represented by a set of equilibrium equations:

$\Sigma F_{x} = -F + \mu_{k}\cdot N = 0$

$\Sigma F_{y} = N-m\cdot g=0$

After some algebraic changes, the expression for the coefficient of static friction comes out as:

$\mu_{k} = \frac{F}{m\cdot g}$

$\mu_{k} = \frac{22.5\,lbf}{150\,lbf}$

$\mu_{k} = 0.15$

3 0

2 months ago

Describe the grain structure of a metal ingot that was produced by slow-cooling the metal in a stationary open mold.

pantera1 [306]

In the scenario of a metal ingot cooling slowly, the microstructure tends to be coarse. The surface, exposed to higher temperatures for extended periods during cooling, features smaller grain sizes as they have less time to form. However, as we delve deeper into the ingot, the grains gradually extend, leading to equiaxed grain formation at the center.

6 0

2 months ago

An insulated box containing helium gas falls from a balloon 4.5 km above the earth's surface. calculate the temperature rise in

iogann1982 [368]

The increase in temperature of the helium gas is calculated to be 14.25 K. The helium is located in an insulated box that falls from a height of 4.5 km. As it descends, the potential energy is transformed into internal energy of the helium gas. The equation for temperature change can be expressed as: 10 x 4.5 = 3.15 x ΔT, yielding a temperature increase of ΔT = 14.25 K.

6 0

2 months ago