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kolezko
10 days ago
5

Torque can be calculated by multiplying the force (N) applied at 90∘ to the lever arm at a distance (m) from the pivot point (po

int of rotation), the compound SI unit for the torque is N⋅m. If the force (at 90∘ to the lever arm) applied is 15 N and it is applied at 2.0 m from the pivot point (point of rotation), what is the torque on the lever?
Physics
1 answer:
Sav [1.1K]9 days ago
4 0
Torque = Force * Distance perpendicular

Torque = 15 N * 2 m = 30 Nm
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A test car carrying a crash test dummy accelerates from 0 to 30 m/s and then crashes into a brick wall. Describe the direction o
Maru [1056]

Answer:

The direction in which a vehicle accelerates aligns with its velocity direction. However, the force of acceleration works against the car's speed.

Explanation:

The car’s initial acceleration can be found using:

v = v₀ + a t

a = (v-v₀) t

which assumes the initial speed is zero (v₀ = 0 m/s).

a = v / t

a = 300 / t

The acceleration vector matches the direction of the vehicle's movement.

Upon hitting the wall, a force is exerted in the reverse direction to halt the car, thus this acceleration opposes the vehicle’s speed. However, the module should be much greater since the stopping distance is minimal.

5 0
4 days ago
The muzzle velocity of a gun is the velocity of the bullet when it leaves the barrel. The muzzle velocity of one rifle with a sh
Keith_Richards [1038]

Answer: small barrel gun

Explanation:

It is noted that short barrel guns have a higher muzzle velocity for bullets compared to longer barrel guns.

Acceleration is determined by the change in velocity with respect to time.

a=\dfrac{\Delta v}{\Delta t}

For short barrel guns, the bullet reaches its muzzle velocity more quickly, leading to greater acceleration than that of bullets from long barrel guns.

7 0
11 days ago
Help asap please!! An aluminum block of mass 12.00 kg is heated from 20 C to 118 C. If the specific heat of aluminum is 913 J-1
Sav [1105]
Q = mCΔT, in which Q = energy required, m = mass of the block, C = specific heat, ΔT = temperature change.

Utilizing the values provided;

Q = 12*913*(118-20) = 1073688 J = 1073.688 kJ.

The correct option is B.
7 0
12 days ago
Daniel takes his two dogs, Pauli the Pointer and Newton the Newfoundland, out to a field and lets them loose to exercise. Both d
Maru [1056]

Answer:

4.05 m/s

Explanation:

We will express the varying velocities as vectors.

Newton moves northward at 3.90 m/s from Daniel's stationary position.

V_n = 3.9 j

Assuming Pauli runs relative to Daniel at velocity X.

The relative velocity of Newton as seen by Pauli will be

3.9 j - X

Given that

the relative velocity of Newton with respect to moving Pauli = 1.1 i (1.1 towards the east).

Thus,

3.9 j - X = 1.1 i

X = -1.1 i + 3.9 j.

Magnitude of X

X² = 1.1² + 3.9²

X = 4.05 m/s

Therefore, Pauli runs relative to Daniel at 4.05 m/s.

The direction will be west of north at an angle θ,

Tan θ = 1.1 / 3.9

4 0
11 days ago
A sphere of radius 0.03m has a point charge of q= 7.6 micro C located at it’s centre. Find the electric flux through it?
Sav [1105]

Answer:

The electric flux going through the sphere is 8.58 *10^{5} \frac{Nm^2}{C}

Explanation:

Given

Radius,\ r = 0.03m\\Charge,\ q =7.6\µC

Required

Calculate the electric flux

Electric flux can be computed using the formula;

Ф = q/ε

Where ε stands for the electric constant permittivity

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Substituting ε = 8.8542 * 10^{-12} and q =7.6\µC; the formula simplifies to

Ф = \frac{7.6\µC}{8.8542 * 10^{-12}}

Ф = \frac{7.6 * 10^{-6}}{8.8542 * 10^{-12}}

Ф = \frac{7.6}{8.8542} *\frac{10^{-6}}{10^{-12}}

Ф = \frac{7.6}{8.8542} *10^{12-6}}

Ф = 0.85834970974 *10^{12-6}}

Ф = 0.85834970974 *10^{6}}

Ф = 8.5834970974 *10^{5}}

Ф = 8.58 *10^{5} \frac{Nm^2}{C}

Thus, the electric flux through the sphere is 8.58 *10^{5} \frac{Nm^2}{C}

7 0
17 days ago
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