Answer:
Confidence limit = [52.8%, 75.2%]
Step-by-step explanation:



±

where the value
will be sourced from the z-table regarding a 95% confidence interval
1-0.95= 0.05/2= 0.025
0.95+0.025= 0.0975
From the z-table, the value of
linked to 0.0975 is 1.96
±

±

± 
% ±
%
thus, the confidence interval is
%
%
![[52.8, 75.2]](https://tex.z-dn.net/?f=%5B52.8%2C%2075.2%5D)
I have included a screenshot of the entire question along with its accompanying diagram.
Answer:∠1 = 163°
Explanation:1- finding angle 2:Given that ∠2 together with 17° creates a straight angle, their total is 180°.
Thus:
180 = 17 + ∠2
Solving for ∠2 gives us:
∠2 = 180 - 17
∠2 = 163°
2- finding angle 1:Since lines a and b are parallel, ∠1 and ∠2 are alternate angles and therefore equal.
We determined that ∠2 = 163°, leading to:
∠1 = 163°
I hope this clarifies things!:)
The solution is found in the image attached below.
The tension does not approach infinity.
<span>Let's analyze free body diagrams (FBDs) for each mass, considering the direction of motion of m₁ as positive.
For m₁: m₁*g - T = m₁*a
For m₂: T - m₂*g = m₂*a
Assuming a massless cord and pulley without friction, the accelerations are the same.
From the second equation: a = (T - m₂*g) / m₂
Substitute into the first:
m₁*g - T = m₁ * [(T - m₂*g) / m₂]
Rearranging:
m₁*g - T = (m₁*T)/m₂ - m₁*g
2*m₁*g = T * (1 + m₁/m₂)
2*m₁*m₂*g = T * (m₂ + m₁)
T = (2*m₁*m₂*g) / (m₂ + m₁)
Taking the limit as m₁ approaches infinity:
T = 2*m₂*g
This aligns with intuition since the greatest acceleration m₁ can have is -g. The cord then accelerates m₂ upward at g while gravity acts downward, leading to a maximum upward acceleration of 2*g for m₁.</span>