Indeed, a reaction will occur as chlorine displaces iodine from its aqueous solution due to its more potent oxidizing properties.
C12(aq) + 2KI(aq) = 2KCI(aq) + I2(aq)
To accomplish this, we must first understand the rules of significant figures.
<span>Rule #1: All digits other than zero are considered significant. (1234)
Rule #2: Leading zeros do not count as significant. (0.093)
Rule #3: Zeros situated between non-zero digits are significant. (78309)
Rule #4: Trailing zeros are significant only if there is a decimal point. (0.05470)
Therefore, considering these rules, 56.0g contains three significant figures due to the decimal point.
0.0004m has just one significant figure per Rule #2.
1003ml contains 4 significant figures because the zeros are between two significant digits.
Lastly, 0.0350s has 3 significant figures because digits following a decimal point are counted.
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Answer:
1. Ionic compound- 
2. Polar molecular compound- 
Explanation:
Magnesium (Mg), with atomic number 12, has an electron configuration of 
. The outermost shell possesses 2 electrons, thus it loses these 2 electrons to become 
ions. Bromine (Br), a nonmetal with atomic number 35, has an electron configuration of 
. Its outermost shell holds 7 electrons, allowing it to accept one electron and thus forms 
. Hence, the magnesium ion and bromide ion bond together to form an ionic compound .
Phosphorus (P), also a nonmetal, bonds with bromine covalently. Due to differing electronegativities, they produce polar covalent compounds like .
H2PO4- acts as a proton donor, whereas HPO42- serves as a proton acceptor. Step 1: Determining hydrogen ion donors and acceptors in the reaction displayed: H2PO4- is predisposed to release a H+ ion to yield HPO42-. On the other hand, HPO42- is inclined to accept a H+ ion, producing H2PO4-. The process of an acid in a water solvent is characterized as dissociation: HA ⇔ H+ + A- where HA denotes a proton acid. Therefore, H2PO4- = HA and HPO42- = A-. Acids are recognized as proton donors, which is why H2PO4- donates protons and HPO42- accepts them.
