A + B → AB: ✔ combination
AB → A + B: ✔ breakdown
Hydrocarbon + O2 → CO2 + H2O: <span>✔ oxidation</span>
AB + CD → AD + CB: <span>✔ exchange</span>
The accurate answer is option 2. When Pt2+ undergoes reduction, it loses electrons, thus oxidizing itself. The oxidation state corresponds to the atom's charge. When an electron is added, the overall charge diminishes, which in turn reduces the oxidation number.
The neutralization reaction that occurs between potassium hydroxide and sulfuric acid can be represented as follows
2KOH + H2SO4 ---> K2SO4 + 2H2O
The quantity of moles of KOH is calculated using (43.74 x 0.500)/ 1000 = 0.02187 moles
Given that the stoichiometric ratio of KOH to H2SO4 is 2:1, the moles of H2SO4 can be determined as 0.02187/2 = 0.01094 moles
To find the concentration (molarity), use the formula (0.01094/50) x 1000 = 0.2188M
Answer:
No
Explanation:
When heated, tin could react with alkali metals, releasing hydrogen gas.
Initially we need to perform the conversion:145 pm = 145 * 10^(-12) m; 36 cm = 360 mm = 360 * 10^(-3) m. Then, we can calculate: 360 * 10^(-3) m / 145 * 10^(-12) m = 360 * 10^(-3) * 10^(12) / 145 = 2.482758621 * 10^(9) or:2,482,758,621 atoms.
