Although multiple values are given, our focus is on HCl.
<span>We have 215 mL (0.215 L) of 0.300 M HCl fully consumed in the reaction. It's important to recall that the number of moles is found by multiplying volume by molarity:</span>
moles = 0.215 L × 0.300 M
<span>moles = 0.0645 moles of HCl</span>
Answer:
Angle ABE measures 27°.
Explanation:
Refer to the attached diagram related to this question.
The given values are ∠ABE=2n+7 and ∠EBF=4n-13.
Clearly seen in the diagram, ∠ABE and ∠EBF are equal in measure.
Move variable components to one side of the equation.
Split both sides by 2.
The solution for n arrives at 10.
The next step is to calculate ∠ABE.
Consequently, the measurement of angle ABE is 27°.
Answer:
Ir(NO2)3
Explanation:
The molar mass is 330.2335, in case that's also required.
Assuming we have a 100g sample, the mass of each element is as follows:
C: 74 g
H: 7.4 g
N: 8.6 g
O: 10 g
Next, we calculate the moles of each by dividing the mass of each element by its molar mass:
C: (74 / 12) = 6.17
H: (7.4 / 1) = 7.4
N: (8.6 / 14) = 0.61
O: (10 / 16) = 0.625
Now, we take the smallest value to determine the ratio:
C: 10
H: 12
N: 1
O: 1
Thus, the empirical formula can be expressed as
C10H12NO
Answer: The right choice is (c) application of both a mobile phase and a stationary phase.
Explanation:
Chromatography: This refers to a technique for separating a mixture where the mixture is distributed between two phases at varying rates, one being stationary and the other moving.
Mobile phase: The component in which the mixture is dissolved is referred to as the mobile phase.
Stationary phase: This is an adsorbent medium that remains in place while a liquid or gas passes over its surface, thus remaining stationary.
Consequently, a key characteristic of any chromatography technique involves utilizing both a mobile and a stationary phase.
