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1 month ago

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Which equation shows the point-slope form of the line that passes through (3, 2) and has a slope of y plus StartFraction one-hal

f EndFraction equals 3 left-parenthesis x minus 2 right-parenthesis.?
y + 2 =y plus 2 equals StartFraction one-third EndFraction left-parenthesis x plus 3 right-parenthesis.(x + 3)
y – 2 = y minus 2 equals StartFraction one-third EndFraction left-parenthesis x minus 3 right-parenthesis.(x – 3)
y + 3 = y plus 3 equals StartFraction one-third EndFraction left-parenthesis x plus 2 right-parenthesis.(x + 2)
y – 3 = y plus StartFraction one-half EndFraction equals 2 left-parenthesis x minus 3 right-parenthesis.(x – 2)

2 answers:

lawyer [12.5K]1 month ago

4 0

Answer:

B. y - 2 = 1/3(x - 3)

PIT_PIT [12.4K]1 month ago

4 0

Answer:

B.

Explanation:

Calculating confirms that the correct answer is B.

You might be interested in

Given that Ray E B bisects ∠CEA, which statements must be true? Select three options. m∠CEA = 90° m∠CEF = m∠CEA + m∠BEF m∠CEB =

tester [12383]

Answer:

Attached is the question in consideration.

$m\angle CEA =90 \ (deg)$

$m\angle BEF=135\ (deg)$

$\angle CEF$ forms a straight line.

$\angle AEF$ depicts a right triangle.

The options $1,4,5,6$ represent the correct answers.

Step-by-step explanation:

⇒ Given that $\ ray\ AE$ is ⊥ $FEC$ it constitutes a right triangle, leading to $m\angle CEA =90\ (deg)$ .

⇒ The measure for $\angle BEF =135\ (deg)$ equals $\angle BEF =\angle AEB +\angle AEF = (45+90)=135\ (deg)$ as $\angle AEB$ bisects $\angle AEC$ , implying that $\angle AEB$ is half of $\angle AEC$ , thus $\angle AEB = 45\ (deg)$ .

⇒ $\angle CEF$ represents a straight line, as the angle measures across it yield $180\ (deg)$ .

⇒ The angle measure for $\angle AEF = 90\ (deg)$ is derived from the linear pair concept.

Since $\angle CEA + \angle AEF = 180\ (deg)$ , inserting the values of $m\angle CEA =90\ (deg)$ leads to $\angle AEF = 90\ (deg)$ .

The other two options are incorrect as:

$m\angle CEF=m\angle CEA + m\angle BEF = (90+135)=225$

it surpasses $180\ (deg)$ while $\angle CEF$ is a

straight line.

Also, $m\angle CEB=2(m\angle CEA)$ is inaccurate.

As $\angle CEA = 90\ (deg)$ and $\angle CEB=45\ (deg)$

Thus, we have a total $4$ valid answers.

The confirmed options are $1,4,5,6$ .

5 0

1 month ago

Read 2 more answers

Venetta buys 2 pounds of pistachios and 3 pounds of almonds. The pistachios cost $4 more per pound than the almonds. She pays a

babunello [11817]

Answer:

A. Combining one pound of pistachios with one pound of almonds costs $20.

C. Decreasing the almond quantity by one pound leads to a total price of $40.

E. The price p (in dollars) per pound of pistachios is represented by the equation 2p + 3(p – 4) = 48.

Step-by-step explanation:

Let:

x = cost per pound of pistachios

y = cost per pound of almonds

We know that

x = y + 4 (Equation A)

2x + 3y = 48 (Equation B)

Substitute x from Equation A into Equation B:

2(y + 4) + 3y = 48

2y + 8 + 3y = 48

5y = 48 – 8

y = 8

Find x:

x = 8 + 4 = 12

Therefore, pistachios cost $12 per pound and almonds cost $8 per pound.

Verify the statements:

Case A) One pound of each equals $20.

True, since 12 + 8 = 20.

Case B) Pistachios cost twice as much as almonds.

False, because 2 × 8 = $16 ≠ $12.

Case C) Reducing almond pounds by 1 yields $40 total.

True, as 2(12) + 2(8) = 24 +16 = 40.

Case D) The almond cost modeled by 2(a – 4) + 3a = 48.

False; it should be 2(a + 4) + 3a = 48.

Case E) The pistachio cost modeled by 2p + 3(p – 4) = 48.

True, since p = a + 4 implies a = p – 4.

8 0

2 months ago

If AE=6x-55 and EC=3x-16, find DB. (Hint: Find x first and then substitute.)

Zina [12379]

Answer:

46 units

Step-by-step explanation:

The diagonals of a rectangle intersect at their midpoints, indicating AE = EC. Therefore, set the equations equal and solve for x:

6x - 55 = 3x - 16

3x = 39

x = 13

Additionally, another characteristic of rectangle diagonals is their equal lengths, hence AC = DB. Now, let’s assess the length of AC:

AC = AE + EC = (6 * 13 - 55) + (3 * 13 - 16) = 23 + 23 = 46

Since AC = DB, it follows that DB = 46 units.

I hope this clarifies your question!

3 0

1 month ago

At Fairview middle school 75 band members need to raise a total for a trip of $8,250 for a trip so far they have raised $3,120 h

AnnZ [12381]

8250-3120=5130

5130/75=68.40

Each member of the band has to contribute $68.40

8 0

25 days ago

Evaluate ∫SF⃗ ⋅dA⃗ , where F⃗ =(bx/a)i⃗ +(ay/b)j⃗ and S is the elliptic cylinder oriented away from the z-axis, and given by x2/

Inessa [12570]

Respuesta:

Por lo tanto, la integral de superficie es $\pi(a^2+b^2)c-0-0=\pi(a^2+b^2)c$ .

Explicación paso a paso:

La función dada es,

$\vec{F}=\frac{bx}{a}\uvec{i}+\frac{ay}{b}\uvec{j}$

Para encontrar,

$\int\int_{S}\vec{F}dS$

donde S=A=superficie del cilindro elíptico debemos aplicar el teorema de divergencia, así que,

$\int\int_{S}\vec{F}dS$

$=\int\int\int_V\nabla.\vec{F}dV$

$=\int\int\int_V(\frac{b}{a}+\frac{a}{b})dV$

$=\frac{a^2+b^2}{ab}\int\int\int_VdV$

$=\frac{a^2+b^2}{ab}\times \textit{Volume of the elliptic cylinder}$

$=\frac{a^2+b^2}{ab}\times \pi ab\times 2c=\pi (a^2+b^2)c$

Si el vector unitario $\cap{n}$ está dirigido en dirección positiva (hacia afuera), entonces z=c y,

$\int\int_{S_1}\vex{F}.dS_1=\int\int_{S_1}. dA$

$=\int\int_{S_1}.dA=0$

Si el vector unitario $\cap{n}$ está dirigido en dirección negativa (hacia adentro), entonces z=-c y,

$\int\int_{S_2}\vex{F}.dS_2=\int\int_{S_2}. -dA$

$=\int\int_{S_2}. -dA=0$

Por lo tanto, la integral de superficie sin el vector unitario de la superficie es,

$\pi(a^2+b^2)c-0-0=\pi(a^2+b^2)c$

5 0

1 month ago