Consider the standard galvanic cell based on the following half-reactions The electrodes in this cell are and . Does the cell po

tential increase, decrease, or remain the same when the following changes occur to the standard cell? You may need to use the following data: Half-Reaction 0.80 0.34 a is added to the silver half-cell compartment (assume no volume change). increases decreases remains the same b is added to the silver half-cell compartment. [Hint: reacts with to form .] increases decreases remains the same c is added to the copper half-cell compartment. [Hint: reacts with to form .] increases decreases remains the same

Chemistry

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Which of the following reactions is a redox reaction? (a) K2CrO4 + BaCl2 → BaCrO4 + 2KCl (b) Pb2+ + 2Br- → PbBr2 (c) Cu + S → Cu

castortr0y [3046]

Explanation:

The following reactions are presented:

(a) K₂CrO₄ + BaCl₂ → BaCrO₄ + 2 KCl

(b) Pb²⁺ + 2 Br⁻ → PbBr₂

Reaction (c) represents a redox reaction, as the oxidation states of the elements are changing. In this case:

Cu + S → CuS

In its elemental form, Cu has an oxidation state of 0, while in CuS (copper sulfide), its oxidation state changes to +2.

Similarly, S in its elemental form has an oxidation state of 0 and is -2 in CuS (copper sulfide).

Learn more about:

redox reactions

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3 months ago

A 0.821 gram sample of pure NH F was treated with 25.0 mL of 1.00 M NaOH

KiRa [2933]

A total of 0.0222 moles of NaOH are necessary to react with NH4F. \nBased on the reaction NH4F + NaOH --> NaF + NH3 + H2O, we start with: \nMass of NH4F = 0.821 g, NaOH concentration = 1 M, volume of NaOH = 25 mL. \nTo find moles: moles of NaOH = (CV)/1000. Thus, moles of NaOH = (1 * 25)/1000 = 0.025 moles of NaOH used. \nThe molar mass of NH4F is 37 g/mol, making moles of NH4F = 0.821 / 37 = 0.0222 moles. \nThis shows that NaOH is in excess, with 0.025 - 0.0222 = 0.0028 moles of NaOH remaining. Hence, 0.0222 moles of NaOH are needed to react with NH4F.

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2 months ago