A student collected the data shown in the table below during an experiment.

Answer:

The mass of 22-Na included in the sample amounts to 0.0599 g

Explanation:

The total mass of the isotope mixture is 1.8385g.

It has an apparent mass of 22.9573 u.

For 23-Na, the relative atomic mass is 22.9898 u, while for 22-Na it is 21.9944 u.

Let the relative abundance of 23-Na be denoted as X.

This means that the relative abundance of 22-Na can be expressed as (1-X).

The equation formed is 21.9944 (1-X) + 22.9898 X = 22.9573.

Rearranging gives: 21.9944 - 21.9944X + 22.9898X = 22.9573.

Which simplifies to 22.9898X - 21.9944X = 22.9573 - 21.9944.

Hence, 0.9954X = 0.9639, leading to X = 0.9674.

The relative abundance of 23-Na is now identified as 0.9674.

Consequently, the relative abundance of 22-Na is 1 - 0.9674 = 0.0326.

Now, the mass of 22-Na contained within the 1.8385g sample is determined by

Relative abundance of 22-Na multiplied by the mass of the total sample = 0.0326 × 1.8385g = 0.0599 g.

The balloon's volume is 128 ml when the gas temperature rises to 320.0 K. Explanation: Given the following: T1 (initial temperature) = 300K, V1 (initial volume) = 120ml, T2 (final temperature) = 320 K, V2 (final volume) =?. Pressure is kept constant during this process. From the equation: Given that the pressure stays constant, we have: V2 = Putting the values into this formula yields: V2 = 128 ml, which indicates the volume of the gas when the temperature increases from 300 K to 320 K.

The soccer field's length is 3.94 × 10^2 in.

Length = 100 m × (39.37 in/1 m) = 394 in = 3.94 × 10^2 in

The mass calculated for the copper piece is 290 grams. The formula for mass is given by mass = density × volume, where the density of copper is 8.96 grams per mL. The volume of the copper piece, determined by the increase in volume, equals 137 mL - 105 mL = 32 mL. Multiplying the volume by the density gives us the mass of copper: mass = 8.96 g/mL × 32 mL = 286.72 grams. Since the volume is presented with two significant figures, rounding the mass to two significant figures results in 290 grams.

Answer:

Al (s) + AgClO3 (aq) will undergo a chemical reaction.

Al(s) + 3AgClO₃(aq) -----> Al(ClO₃)₃(aq) + 3Ag(s)

Cd(s) + CuNO3(aq) will also engage in a chemical reaction.

Cd(s) + 2CuNO₃ -----> Cd(NO₃)₂ + 2Cu

Explanation:

In chemical reactions, metal elements positioned lower in the activity series typically cannot replace those positioned higher in the series.

Metals located lower on the activity series are less likely to oxidize.

The activity series is referenced in this solution. (Note: While Cadmium is not directly illustrated, it falls between Iron (Fe) and Cobalt (Co) within the series.)

- Lead is significantly lower than Magnesium in the activity series, so it cannot displace Mg2+ ions in a solution.

- Aluminium ranks higher than Silver in the series; thus, it can easily oxidize and replace Silver ions from its solution.

- Cadmium is capable of displacing Copper in solution since it ranks higher than Copper in the activity series.

- Platinum is unable to displace Cobalt from a solution, as it ranks lower than Cobalt in the activity series.