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oee
7 hours ago
11

The atmosphere pressure can support mercury in a tube, which the upper end is closed, up to 0.76 meter. If the mercury is replac

ed by pure water in this case, what is the maximum height the atmosphere pressure can support the water in such kind a tube? (The density of mercury is about 13.6 times larger than that of water).
Physics
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A rocket is continuously firing its engines as it accelerates away from Earth. For the first kilometer of its ascent, the mass o
kicyunya [3294]

Answer:

The correct response is:

1. KE Increases, PE Increases, ME Increases.

Explanation:

In this context, kinetic energy refers to the energy associated with an object's motion. Kinetic energy can be defined as the energy required to accelerate a mass from rest to a specified velocity, which it maintains once that speed is reached:

KE = 1/2 mv².

This definition indicates that KE is on the rise.

Potential energy is the energy stored in a body due to its position in a gravitational field:

PE = mgh,

which increases as the object is elevated against gravitational pull.

Since both kinetic and potential energies are increasing, it follows that the total mechanical energy (ME) is also rising:

ME = PE + KE.

4 0
2 months ago
Read 2 more answers
A parallel-plate capacitor is constructed of two square plates, size L×L, separated by distance d. The plates are given charge ±
inna [3103]

Answer: A) 2 B) 4 C) 1

Explanation:

The electric field associated with a parallel-plate capacitor is defined as:

A) E=Q/(L^2 * ε0); if we double the charge, the resultant electric field becomes twice as strong as its initial value.

B) Referring to the earlier electric field expression, if the plate size is doubled, the final electric field will be a quarter of the original strength.

C) If the separation distance between the plates is increased twofold, the resulting electric field remains unchanged from its initial state.

3 0
2 months ago
Modern wind turbines generate electricity from wind power. The large, massive blades have a large moment of inertia and carry a
Yuliya22 [3333]

Answer:

Explanation:

a )

Each blade resembles a rod with its axis positioned near one end.

The moment of inertia for one blade is:

= 1/3 x m l²

where m stands for the mass of the blade

l represents the length of each blade.

Total moment of inertia for 3 blades is:

= 3 x\frac{1}{3}  x m l²

ml²

2 )

Details provided include:

m = 5500 kg

l = 45 m

Substituting these values produces:

moment of inertia of one blade:

= 1/3 x 5500 x 45 x 45

= 37.125 x 10⁵ kg.m²

Moment of inertia for 3 blades:

= 3 x 37.125 x 10⁵ kg.m²

= 111.375 x 10⁵ kg.m²

c )

Angular momentum

= I x ω

I denotes the moment of inertia of the turbine

ω symbolizes angular velocity

ω = 2π f

f indicates the rotational frequency of the blades

d )

We have I = 111.375 x 10⁵ kg.m² (Calculated)

f = 11 rpm (revolutions per minute)

= 11 / 60 revolutions per second

ω = 2π f

=  2π x  11 / 60 rad / s

Calculating angular momentum yields

= I x ω

111.375 x 10⁵ kg.m² x  2π x  11 / 60 rad / s

= 128.23 x 10⁵  kgm² s⁻¹.

4 0
3 months ago
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