To address this issue, we apply the de Broglie equation written as:
λ = h/mv
where h equals 6.626×10⁻³⁴ J·s
Solving for m, we substitute for v, which is 46.9 m/s:
9.74 × 10⁻³⁵ m = 6.626×10⁻³⁴ J·s / (m)(46.9 m/s)
Thus, we find that m = 0.145kg
Answer:
h = 1/50 v₀² g
Explanation:
This scenario illustrates conservation of momentum; the system comprises two bodies, hence forces during the collision are internal and momentum remains conserved.
Prior to the collision
po = 0 + (m/4) vo
Post collision
pf = (m + m/4) v
pf = (5m/4) v
m/4 vo = (5m/4) v
v = 1/5 vo
This indicates that after impact, the bodies travel at 1/5 of their initial velocity.
To determine the maximum height, we will apply the law of energy conservation.
At the peak post-collision
Em = K = ½ (5m / 4) v²
At the apex
Em = U = (5m/4) g h
½ (5m/4) v² = (5m/4) g h
h = ½ v² / g
h = ½ (1/5 v₀)² / g
h = 1/50 v₀² g
Answer:
Term 1 = (0.616 × 10⁻⁵)
Term 2 = (7.24 × 10⁻⁵)
Term 3 = (174 × 10⁻⁵)
Term 4 = (317 × 10⁻⁵)
(σ ₑ/ₘ) / (e/m) = (499 × 10⁻⁵) rounded to the correct significant figures.
Explanation:
(σ ₑ/ₘ) / (e/m) = (σᵥ /V)² + (2 σᵢ/ɪ)² + (2 σʀ /R)² + (2 σᵣ /r)²
average values
Voltage, V = (403 ± 1) V,
σᵥ = 1 V, V = 403 V
Current, I = (2.35 ± 0.01) A
σᵢ = 0.01 A, I = 2.35 A
Radius of coils, R = (14.4 ± 0.3) cm
σʀ = 0.3 cm, R = 14.4 cm
Radius of curvature of electron path, r = (7.1 ± 0.2) cm.
σᵣ = 0.2 cm, r = 7.1 cm
Term 1 = (σᵥ /V)² = (1/403)² = 0.0000061573 = (0.616 × 10⁻⁵)
Term 2 = (2 σᵢ/ɪ)² = (2×0.01/2.35)² = 0.000072431 = (7.24 × 10⁻⁵)
Term 3 = (2 σʀ /R)² = (2×0.3/14.4)² = 0.0017361111 = (174 × 10⁻⁵)
Term 4 = (2 σᵣ /r)² = (2×0.2/7.1)² = 0.0031739734 = (317 × 10⁻⁵)
The relative e/m value is the total of all the computed terms.
(σ ₑ/ₘ) / (e/m)
= (0.616 + 7.24 + 174 + 317) × 10⁻⁵
= (498.856 × 10⁻⁵)
= (499 × 10⁻⁵) rounded to the required significant figures.
Hope this Helps!!!
Answer:
2.34 L
Explanation:
Assuming the pressure within the balloon is held steady, we can apply Charle's law which states that for a gas at constant pressure, the ratio of its volume to temperature remains unchanged:
In our scenario:
is the initial volume
is the final volume
is the starting temperature
is the concluding temperature
By plugging values into the equation and resolving for V2, we can calculate the final volume:
