<span>We can deduce distance using the equation d = [(v_f^2) - (v_i^2)]/(2a).
So, d = [(0^2)-(15^2)]/(2*-7)
d = [0-(225)]/(-14)
d = 225/14
d = 16.0714 m
Considering two significant figures, the roller coaster covers approximately 16 meters as it decelerates.</span>
Heat capacity of A is three times that of B
and the initial temperature for A is twice that of B
with TA = 2 TB
Let T denote the final temperature of the system.
The heat lost by A equals the heat gained by B:
mass of A x specific heat of A x (TA - T) = mass of B x specific heat of B x ( T - TB)
which simplifies to heat capacity of A x ( TA - T) = heat capacity of B x ( T - TB)
resulting in 3 x heat capacity of B x ( TA - T) = heat capacity of B x ( T - TB).
This leads us to the equation: 3 TA - 3 T = T - TB
which rearranges to yield 6 TB + TB = 4 T
thus giving us T = 1.75 TB
Refer to the diagram below.
This discussion operates under a basic analysis that overlooks air resistance and variations in the terrain the missile traverses.
Let V₀ be the launch velocity, at an angle θ to the horizontal.
The horizontal velocity component equals V₀ cosθ.
If the flight duration is

, then

where r represents the missile's range.
The time t at which the missile is at ground level is expressed by

where g signifies acceleration due to gravity.
t = 0 signifies the missile's launch. Thus

Consequently,

Typically, an angle of θ=45° is optimal for achieving maximum range, resulting in

This discussion applies more accurately to a scud missile than to a powered, guided missile.
Response:

Usually, θ=45°
None of the provided options is correct. After contact, A becomes -4 µC, B remains 0 µC, and C ends with +4.0 µC. When spheres A and B touch, charges will redistribute to establish balance, resulting in A = -4 µC, B = -4 µC, C = +4.0 µC. After C and B are touched, both positive and negative charges neutralize each other, leaving A at -4 µC, B at 0 µC, and C at 0 µC.