Utilizing the equation F = ma, where F represents the force applied by the machine, A denotes acceleration (equivalent to v/t, with v as velocity and t as time), and M symbolizes mass, we can calculate as follows: F = mv/t. Thus, F = (0.15kg) (30 – 0 m/s) / 0.5 s, resulting in F = 9 N.
Answer:
Insufficient details provided; please clarify further.
The formula used is known as the Law of Universal Gravitation. The gravitational constant G is 6.67×10⁻¹¹ Nm²/kg². The Earth's mass is <span>5.972 ×10</span>²⁴ kg. The mass of the rocket is negligible in comparison to Earth’s mass, hence it is unnecessary for our calculations. Plugging in the values:
F = (6.67×10⁻¹¹ Nm²/kg²)(5.972 ×10²⁴ kg)/(4000 miles*(1.609 km/1 mile))²
F = 9616423.08 N
The work done is given by
W = Fd
W = (9616423.08 N)(2000 miles*1.609 km/mile)
W = 9.095×10¹⁰ Joules
Answer:
The value of Y is -10°.
Explanation:
For scale X, the freezing point is 40° and the boiling point is 120°.
The gap between the two endpoints for scale X = 120 - 40 = 80
For scale Y, the ice point and steam point are -30° and 130° correspondingly.
The difference between these two points for scale Y = 130 - (-30) = 160
Comparing both scales:
One unit in scale X is x
One unit in scale Y is y
Scale X consists of 80 divisions, while scale Y has 160
80x = 160y
x = 2y
50° on scale X equals 10x plus the freezing point of scale X
10 divisions in scale Y correspond to 20y
The reading on scale Y = the ice point of Y + 20y
= -30° + 20°
= -10°
This method is termed dimensional analysis, which focuses solely on the measurement units without considering their values. You need to perform calculations using variables while eliminating similar items from both the numerator and denominator. The outcome is as follows:
F = mv²/r = [kg][m/s]²/[m] = [kg][m²⁻¹][1/s²] = [kg·m/s²].
