The height from which the glasses fell is s = 23.72 m and the impact speed is v = 21.56 m/s². Explanation: Using the time taken to hit the ground (t) = 2.2 seconds, we can apply the formula s = u t + 0.5 g t² with initial velocity u = 0 m/s and g = 9.8 m/s²: s = 0 + 0.5 × 9.8 × 2.2², resulting in s = 23.72 m. For the impact velocity, we use the equation v = √(2gh), yielding v = √(2 × 9.8 × 23.72) = √464.912, leading to v = 21.56 m/s².
1. τbiceps = +(Positive)
2. τforearm = -(Negative)
3. τball = -(Negative)
Explanation:
The attached figure illustrates the following: 1. For the biceps, τbiceps indicates that torque is calculated as Torque = r x F, where r and F are vectors. Here, r corresponds to the vector from the elbow to the biceps. In the figure, the force from the biceps is directed upwards. Applying the right-hand rule from r to F results in counterclockwise torque, which is considered positive (+).
2. The torque related to the weight of the forearm, τforearm, uses the same torque formula, with r being the vector from the elbow to the forearm. The weight acts downward, causing a clockwise torque that is negative (-).
3. Similarly, for the weight of the ball, τball, the downward force from the ball's weight generates a clockwise torque, which also registers as negative (-).
Answer:
The energy expected to be released is calculated to be 4182 Joules.
Explanation:
The total mass of coke is 2 kg, which is equivalent to 2000 g
1 calorie per gram corresponds to 4.184 Joules of energy
4.184 J/gC * 2000g results in 8368 J
1 food calorie approximates to 4186 J
By subtracting, we find 8368 - 4186
Hence, the total energy that will be released amounts to 4182 Joules.
Answer:
Explanation:
Provided:
The trolley, with mass M, is allowed to roll freely without friction.
The coefficient of friction between the trolley and mass m is 
.
A force F is applied to mass m.
The acceleration of the system is
The frictional force will counterbalance the weight of the block.
The frictional force is 
Arginine is classified as a basic amino acid since it has two amino groups alongside a single acid group.
At a low pH level, all ionizable groups are protonated. As the pH rises slightly, the acid group loses its proton. When the pH increases further, one of the amino groups also loses a proton. At considerably high pH levels, none of the ionizable groups remain protonated.
Pkas
<span>
<span><span>
<span>
pka1 = 1.82
</span>
<span>
pka2 = 8.99
</span>
<span>
pka3 = 12.48
</span>
</span>
</span></span>
Thus, 9.20 is above the second pKa and below the third pKa. This indicates that the acid has already lost its proton, as has one of the amino groups, while the second amino group remains protonated. When an acid is not protonated, it carries a negative charge. An unprotonated amino group is neutral, whereas when protonated, the amino group bears a positive charge. Therefore, this amino acid exhibits one positive charge (from one of the amino groups) and one negative charge (from the acid), resulting in an overall neutral charge.
