2. Un ciclista que está en reposo comienza a pedalear hasta alcanzar los 16.6km/h en 6 minutos. Calcular la distancia total que

a pebble is dropped down a well and hits the water 1.5 seconds later. using the equations for motion with constant acceleration,

inna [3103]

Definamos h como la distancia que hay desde el borde del pozo hasta la superficie del agua (en metros).

Consideremos la gravedad g como 9.8 m/s² y despreciemos la resistencia del aire.

La velocidad inicial vertical del guijarro es nula.
Ya que el guijarro impacta el agua tras 1.5 segundos, entonces:
h = 0.5 * (9.8 m/s²) * (1.5 s)² = 11.025 m

Resultado: 11.025 m

7 0

3 months ago

Read 2 more answers

The magnitude of the electric current is inversely proportional to the _____ of the circuits in R2D2.

Keith_Richards [3271]

The essential principle for this question is Ohm’s Law: V=IR, I=V/R, R=V/I. Therefore, the answer is (3) Resistance, as it is inversely related to Current (I=V/R).

4 0

1 month ago

Two frictionless lab carts start from rest and are pushed along a level surface by a constant force. Students measure the magnit

Yuliya22 [3333]

Answer:

The kinetic energy is higher for the first cart.

Explanation:

For the second cart, its mass is 2kg and the momentum measured is 10kg m/s, which leads to

$(2kg)v = 10kg\: m/s$

resulting in

$v = 5m/s$ .

Consequently, the kinetic energy for the 3kg cart ends up as

$K.E. = \dfrac{1}{2}mv^2$

$= \dfrac{1}{2}(2kg)(5m/s)^2 = 25J$

$\boxed{K.E = 25J}$

indicating it is less than that of the 1kg cart so it follows that the first cart possesses greater kinetic energy.

3 0

3 months ago

A girl and boy pull in opposite directions on a stuffed animal. The girl exerts a force of 3.5 N. The mass of the stuffed animal

Keith_Richards [3271]

I will assume the girl is on the right while the boy is on the left.
The net force represents the total of all forces acting on an object, factoring in negatives.
Let the force from the boy be denoted as b. We’ll apply the formula F = ma.

b + 3.5 = 0.2(2.5)

This reduces to a straightforward algebraic problem. By solving, we find that the boy is applying a force of -3N to the left.

5 0

3 months ago

Read 2 more answers

A block of mass m, initially held at rest on a frictionless ramp a vertical distance H above the floor, slides down the ramp and

kicyunya [3294]

Answer:

$\displaystyle W=-m.g.H$

Explanation:

Transformation of Energy

Also known as energy conversion, this refers to the process in which energy shifts from one type to another. In this context, three energy forms are involved. When the object is stationary at the ramp's peak, it possesses gravitational potential energy, calculated as

$U=m.g.H$

As the object descends the frictionless ramp, it converts all its potential energy into kinetic energy, represented as

$\displaystyle K=\frac{m.v^2}{2}$

Thus,

$K=m.g.H$

Ultimately, when the object encounters a rough surface, all energy converts to thermal energy. The work performed by the friction force corresponds to the alteration in kinetic energy, as all velocity is lost in this process:

$\displaystyle W=\Delta E=K_f-K=0-K=-\frac{m.v^2}{2}$

Given the kinetic energy equals the initial potential energy:

$\boxed{\displaystyle W=-m.g.H}$

The negative sign indicates that the work acted against the direction of movement, meaning the force and displacement are 180° apart.

This outcome is independent of the distance D needed to halt the block or the kinetic friction coefficient.

7 0

3 months ago