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9 days ago

A microwave oven operates at 2.60 ghz . what is the wavelength of the radiation produced by this appliance?

1 answer:

8 0

10.3 cm Wavelength is calculated by dividing the distance light travels in one second by the radiation frequency. Operating at 2.60 GHz, the frequency translates to 2.6 billion cycles per second, or 2.60 x 10^9. The speed of light is defined precisely as 299792458 m/s. Thus, 299792458 m/s / 2.60 x 10^9 1/s = 0.10337671 m = 10.337671 cm Considering only three significant figures, we round this to 10.3 cm.

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A semi is traveling down the highway at a velocity of v = 26 m/s. The driver observes a wreck ahead, locks his brakes, and begin

Yuliya22 [2962]

Answer:

fcosθ + Fbcosθ =Wtanθ

Explanation:

Refer to the provided diagram in the attachment

fx= fcosθ (fx: x-direction component of friction force; f: frictional force)

Fbx= Fbcosθ (Fbx: x-direction component of braking force; Fb: braking force)

Wx= Wtanθ (Wx: x-direction component of weight; W: weight of the semi)

Sum of forces in the x-direction = 0

fx + Fbx = Wx

fcosθ + Fbcosθ =Wtanθ

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1 month ago

Imagine you are riding on a yacht in the ocean and traveling at 20 mph. You then hit a golf ball at 100 mph from the deck of the

ValentinkaMS [3084]

As per Einstein's theory of special relativity, the light speed in a vacuum remains constant regardless of the observer's speed. Therefore, the response should be A) 0.1c (one-tenth the speed of light)

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26 days ago

Read 2 more answers

A 1.97-pF capacitor with a plate area of 5.86 cm2 and separation between the plates of 2.63 mm is connected to a 9.0-V battery a

inna [2732]

If the plate separation is modified after the battery is disconnected, the updated distance between plates is 9.21 mm

If changes are made while the battery remains connected, the new separation becomes 0.11 mm

The capacitance for an air-filled parallel plate capacitor can be expressed as:

$C=\frac{\epsilon_0A}{d}$

In this equation, $\epsilon_0$ refers to the permittivity of free space, A stands for the plate area, and D represents the separation distance.

Thus,

$C \alpha \frac{1}{d}$ .......(1)

Therefore, should the distance between the plates shift from d₁ to d₂, the capacitance ratio in both scenarios can be represented as:

$\frac{C_1}{C_2} =\frac{d_2}{d_1}$ ......(2)

Scenario (i)

When the capacitor is fully charged and then disconnected from the battery before adjusting the plate distance, the charge will remain steady while the capacitance varies.

The initial energy E₁ stored in the capacitor can be expressed as:

$E_1=\frac{Q^2}{2C_1}$ ......(3)

Once the separation changes to d₂, capacitance becomes C₂, but the charge Q remains unchanged.

Thus,

$E_2=\frac{Q^2}{2C_2}$ ......(4)

By dividing equation (4) by (3),

$\frac{E_2}{E_1} =\frac{C_1}{C_2}$

According to equation (2),

$\frac{E_2}{E_1} =\frac{C_1}{C_2}=\frac{d_2}{d_1}$

This results in a 3.5 fold increase in energy.

$\frac{E_2}{E_1} =\frac{d_2}{d_1}=3.5\\ d_2=3.5*2.63 mm\\ =9.205 mm=9.21 mm$

Scenario (2)

If the capacitor is kept connected to the power source, the voltage V across the plates will remain unchanged.

The initial energy is described as

$E_1=\frac{1}{2} C_1V^2$ ......(5)

The final energy when the plate separation transitions to d₂ can be written as:

$E_2=\frac{1}{2} C_2V^2$ .....(6)

Referencing equations (5) and (6)

$\frac{E_2}{E_1} =\frac{C_2}{C_1}$

From equation (2),

$\frac{E_2}{E_1} =\frac{C_2}{C_1}=\frac{d_1}{d_2}$

Thus, in this particular scenario,

$\frac{E_2}{E_1} =\frac{d_1}{d_2}\\d_2=\frac{d_1}{3.5} \\ =\frac{2.63 mm}{3.5} \\ =0.109 mm=0.11 mm$

Therefore,

Adjusting plate separation after battery disconnection yields 9.21 mm

If modified while connected, the new separation measures 0.11 mm

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A group of students prepare for a robotic competition and build a robot that can launch large spheres of mass M in the horizonta

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No one is going to handle that for a mere 5 points lol.

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1 month ago

In an inertial frame of reference, a series of experiments is conducted. in each experiment, two or three forces are applied to

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Objects will stay in a stationary position if the total force acting on them amounts to zero; this occurs when equal forces are applied in opposite directions. According to Newton's second law, if the net force on an object is zero, it will not move.

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29 days ago