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Galina-37
1 month ago
6

There is a distinction between average speed and the magnitude of average velocity. Give an example that illustrates the differe

nce between these two quantities.
Physics
1 answer:
Sav [3.1K]1 month ago
5 0

An instance that highlights the distinction is circular motion

Explanation:

Let's begin with the definitions of these two terms:

- Speed is a scalar quantity that measures "how quickly" an object moves, independent of its travel direction.

Speed can be calculated as:

speed = \frac{d}{t}

where:

d is the distance covered

t is the time elapsed

- Velocity is a vector quantity defined as:

velocity = \frac{d}{t}

where;

d is the object's displacement (a vector connecting initial and final positions during motion)

t is the time taken

Since it is a vector, velocity incorporates both a magnitude and direction, hence taking into account the object's movement direction.

For straight-line motion, speed and velocity are equivalent. However, this isn't always true.

In reality, one scenario where these quantities diverge is in circular motion. For instance, when an object completes a full revolution around the circle, its average speed is calculated as the perimeter length (distance) divided by the time taken:

speed = \frac{2\pi r}{t}

where r denotes the circle's radius.

Nevertheless, since the object's displacement returns to zero (as it goes back to the initial point), the average velocity equals zero:

velocity = \frac{0}{t}=0

Learn more about speed and velocity:

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A box of mass 3.1kg slides down a rough vertical wall. The gravitational force on the box is 30N . When the box reaches a speed
Ostrovityanka [3204]

Answer:

Explanation:

a) La fuerza neta que actúa sobre la caja en la dirección vertical es:

Fnet=Fg−f−Fp *sin45 °

aquí Fg representa la fuerza gravitacional, f es la fuerza de fricción, y Fp es la fuerza de empuje.

Fnet=ma

ma=Fg−f−Fp *sin45 °

​a=\frac{30-13-23*sin(45)}{3.1}

=0.24 m/s²

Vf =Vi +at

=0.48+0.24*2

Vf=2.98 m/s

b)

Fnet=Fg−f−Fp *sin45 °

=Fg−0.516Fp−Fp *sin45 °

=30-1.273Fp

Fnet=0 (Ya que la velocidad es constante)

Fp=30/1.273

=23.56 N

5 0
1 month ago
Read 2 more answers
A horse does 860 j of work in 420 seconds while pulling a wagon. what is the power output of the horse? round your answer to the
Keith_Richards [3271]
the answer is 2w
6 0
20 days ago
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An archer fires an arrow, which produces a muffled "thwok" as it hits a target. If the archer hears the "thwok" exactly 1 s afte
Ostrovityanka [3204]

Answer:

35.79 meters

Explanation:

We have an archer, and there is a target. Denote the distance between them as d.

The bowman releases the arrow, which travels the distance d at a velocity of 40 m/s until it hits the target. We establish the equation as:

v_{arrow} * t_{arrow} = d\\ \\40 \frac{m}{s} * t_{arrow} = d

Right after this, the arrow produces a muffled noise, traveling the same distance d at a speed of 340 m/s in time t_{sound}. Thus, we can derive:

v_{sound} * t_{sound} = d\\ \\340 \frac{m}{s} * t_{sound} = d.

Consequently, the sound reaches the archer, precisely 1 second post-firing the bow, resulting in:

t_{arrow} + t _{sound} = 1 s.

Using this relationship in the distance formula for sound allows us to write:

340 \frac{m}{s} * t_{sound} = d \\ \\ 340 \frac{m}{s} * (1 s- t_{arrow}) = d.

Substituting the value of d from the first equation yields:

40 \frac{m}{s} * t_{arrow} = d \\ 40 \frac{m}{s} * t_{arrow} = 340 \frac{m}{s} * (1 s- t_{arrow}).

Now, after some calculations, we can proceed further:

40 \frac{m}{s} * t_{arrow} = 340 \frac{m}{s} * 1 s - 340 \frac{m}{s} * t_{arrow} \\ \\ 40 \frac{m}{s} * t_{arrow} + 340 \frac{m}{s} * t_{arrow} = 340 m \\ \\ 380 \frac{m}{s} * t_{arrow} = 340 m \\ \\ t_{arrow} = \frac{340 m}{380 \frac{m}{s}} \\ \\ t_{arrow} = 0.8947 s.

Finally, the value is inserted into the initial equation:

40 \frac{m}{s} * t_{arrow} = d

40 \frac{m}{s} * 340/380 s = 35,79 s = d

6 0
26 days ago
Compare the momentum of a 6,300-kg elephant walking 0.11 m/s and a 50-kg dolphin swimming 10.4 m/s. your answer
inna [3103]
<span>First, apply Newton's second law of motion: F = ma. Force equals mass times acceleration. This law describes force as the product of mass multiplied by acceleration (which is different from velocity). As acceleration is the variation in velocity over time, we have force = (mass * velocity) / time, leading us to conclude that (mass * velocity) / time will equal momentum / time. Hence, we derive the equation mass * velocity = momentum. Momentum = mass * velocity. For the elephant, with a mass of 6300 kg and velocity of 0.11 m/s, Momentum = 6300 * 0.11, resulting in P = 693 kg (m/s). For the dolphin, having a mass of 50 kg and moving at 10.4 m/s, Momentum = 50 * 10.4, yielding P = 520 kg (m/s). Thus, the elephant has a greater momentum (P) due to its larger size.</span>
5 0
1 month ago
A student wishes to determine the heat capacity of a coffee-cup calorimeter. After she mixes 108.7 g of water at 60.2°C with 108
Ostrovityanka [3204]

Answer: The calorimeter's heat capacity is 6.72J/g^oC

Explanation:

This scenario assumes the amount of heat lost by the hot object equals the amount of heat gained by the cold object.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat capacity of water = 4.184J/g^oC

c_2 = specific heat capacity of calorimeter =?

m_1 = mass of water = 108.7 g

m_2 = mass of calorimeter = 108.7 g

T_f = final temperature of the mixture = 35.0^oC

T_1 = initial temperature of the water = 60.2^oC

T_2 = initial temperature of calorimeter = 19.3^oC

Now substituting all provided values into the formula, we obtain

(108.7g)\times (4.184J/g^oC)\times (35.0-60.2)^oC=-(108.7g)\times c_2\times (35.0-19.3)^oC

c_2=6.72J/g^oC

Hence, the heat capacity of the calorimeter is 6.72J/g^oC

3 0
1 month ago
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