All categories

3 months ago

At which latitudes shown in the image of Earth do people experience the greatest tangential speed? Explain why.

2 answers:

7 0

The tangential speed of an object is influenced by its distance from the center of the circle. The further away an object is from the center, the quicker it must move. Consequently, individuals residing at a latitude of 0 degrees experience the highest tangential speed.

ValentinkaMS [3.4K]3 months ago

3 0

Sample Response: The tangential speed is determined by how far the object is from the center of the circle. The farther from the center, the faster the object needs to go. Thus, people who live at 0 degrees latitude experience the highest tangential speed.

You might be interested in

A 10-turn conducting loop with a radius of 3.0 cm spins at 60 revolutions per second in a magnetic field of 0.50T. The maximum e

kicyunya [3294]

Answer:

Maximum emf = 5.32 V

Explanation:

Provided data includes:

Number of turns, N = 10

Radius of loop, r = 3 cm = 0.03 m

It made 60 revolutions each second

Magnetic field, B = 0.5 T

We are tasked to determine the maximum emf produced in the loop, which is founded on Faraday's law. The induced emf can be calculated by:

$\epsilon=\dfrac{d(NBA\cos\theta)}{dt}\\\\\epsilon=NBA\dfrac{d(\cos\theta)}{dt}\\\\\epsilon=NBA\omega \sin\omega t\\\\\epsilon=NB\pi r^2\omega \sin\omega t$

For the maximum emf, $\sin\omega t=1$

Therefore,

$\epsilon=NB\pi r^2\omega \\\\\epsilon=NB\pi r^2\times 2\pi f\\\\\epsilon=10\times 0.5\times \pi (0.03)^2\times 2\pi \times 60\\\\\epsilon=5.32\ V$

Hence, the maximum emf generated in the loop is 5.32 V.

3 0

3 months ago

A car traveling at 70 mph70 mph down the interstate collides with a bug trying to cross the highway. Which of the following stat

Sav [3153]

The force exerted by the car on the bug is identical to the force the bug applies back on the car.

5 0

1 month ago

The same physics student jumps off the back of her Laser again, but this time the Laser is

Yuliya22 [3333]

a) The student's speed after jumping is 1.07 m/s

b) The final speed of the laser is 10.4 m/s

Explanation:

This issue can be approached through the momentum conservation principle: In the absence of external forces, the combined momentum of the student and the laser must remain unchanged. Hence, we can express:

$p_i = p_f\\0=mv+MV$

where:

The initial momentum is zero

m = 42 kg signifies the mass of the laser

v = 1.5 m/s is the laser's final velocity

M = 59 kg is the mass of the student

V denotes the student's final velocity

Solving this for V, we can determine the student's speed:

$V=-\frac{mv}{M}=-\frac{(42)(1.5)}{59}=-1.07 m/s$

Thus, the student's final speed calculates to 1.07 m/s.

Here, both the laser and the student have a combined speed of 3.1 m/s prior to the student's jump; thus, the initial momentum isn't zero.

<pSo, we formulate the equation of momentum conservation as:

$(m+M)u=mv+MV$

where:

m = 42 kg denotes the mass of the laser

M = 59 kg is the student’s mass

u = 3.1 m/s is their starting velocity

V = -2.1 m/s indicates the student's speed post-jump (she jumps backward)

v signifies the laser's final speed

When we resolve for v, we have:

$v=\frac{(m+M)u-MV}{m}=\frac{(42+59)(3.1)-(59)(-2.1)}{42}=10.4 m/s$

Learn more about momentum:

3 0

3 months ago

Read 2 more answers