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Rudiy27
23 days ago
11

Un camión cargado, de masa 3000 kg, ha adquirido en la bajada de un puerto una velocidad excesiva de 108 km/h. Al ver una curva

cerca, aprovecha un carril de frenada sin pendiente y se mete en él. El carril tiene una longitud de 100 m. a) ¿Qué energía cinética tiene el camión cuando entra en el carril de frenada? b) ¿Qué trabajo realizan las fuerzas de rozamiento con el suelo para lograr pararlo? c) ¿Qué fuerza se ha hecho sobre el camión para llegar a pararlo a un metro del final del carril?
Physics
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You apply the brakes of your car abruptly and your book starts sliding off the front seat. Three observers sitting in the car ex
Softa [3030]

Answer:

All observers are accurate.

Explanation:

This situation reflects a matter of reference frames regarding the book's motion as perceived by different observers.

From their distinct frames of reference, each observer's perspective is valid.

Observer A is in an inertial reference frame.

Observers capable of explaining the book's behavior and its relationship to the car through the interplay of forces and changes in velocity are classified as being in inertial reference frames.

Observer A's observations illustrate this, for she pointed out the relative motion between the book and the car, indicating her position in an inertial reference frame.

Likewise, observers in these inertial reference frames can elucidate object velocity changes based on the forces affecting them from other objects.

This is exemplified by observer B, who notes the car's force impacting the book's velocity.

Observer C occupies a non-inertial reference frame, as Newton's laws of motion do not apply. This scenario arises within non-inertial frames.

7 0
3 months ago
Suppose you analyze standardized test results for a country and discover almost identical distributions of physics scores for fe
kicyunya [3294]

Answer:

consult a teacher

Explanation:

go to your school

locate the teacher

request assistance from him/her

complete the question and you're done:)

7 0
3 months ago
If a 50.0-kg mass weighs 554 n on the planet saturn, calculate saturn’s radius
ValentinkaMS [3465]

Answer:

17.35 × 10^(-6) m

Explanation:

Mass; m = 50 kg

Weight; W = 554 N

From the formula:

W = mg

This simplifies to; 554 = 50g

g = 554/50

g = 11.08 m/s²

Also, using the formula;

mg = GMm/r²

hence; g = GM/r²

Rearranging gives;

r = √(GM/g)

With G as a known constant of 6.67 × 10^(-11) Nm²/kg²

r = √(6.67 × 10^(-11) × 50/11.08)

r = 17.35 × 10^(-6) m

8 0
3 months ago
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