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yarga
21 day ago
5

A pair of spur gears with 20 degree pressure angle, full-depth, involute teeth transmits 65 hp. The pinion is mounted on a shaft

connected to a 4 cylinder diesel engine that operates at 1250 rpm in the clockwise direction. The pinion has 26 teeth and a diameteral pitch of 6. The gear has 48 teeth and drives a concrete mixer. The gears are manufactured to an AGMA quality number of A11. The face width of the gears is 3 inches and are machined from solid bar stock (blanks). The gears are enclosed in a commercial gear box.
1. What is the pitch line speed of the gear train in feet per minute?
2. What is the center distance of the gear pair in inches?
3. What is the torque on the pinion in Lbin?
4. What is the torque on the gear in lbin?
5. What is the output horsepower of the gearbox?
6. What is the tangential force acting on the gear teeth (Wt) in pounds?
7. What is the radial force acting on the gear teeth in pounds?
8. What is the normal force acting on the gear teeth in pounds?
9. What is the bending stress for the pinion teeth (St) in PSI ?
Engineering
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A 90-hp (shaft output) electric car is powered by an electric motor mounted in the engine compartment. If the motor has an avera
pantera1 [306]

Answer:

Heat supply rate is measured at 8.901 horsepower.

Explanation:

Energy efficiency of the electric vehicle, as per Thermodynamics (\eta), is the proportion of translational mechanical power (\dot E_{out}), expressed in horsepower, and electrical energy (\dot E_{in}), also in horsepower. The heat supply rate (\dot E_{l}), indicated in horsepower, that the motor delivers to the engine bay under full load can be determined by subtracting the translational mechanical energy from the electric energy. This is expressed as:

\eta = \frac{\dot E_{out}}{\dot E_{in}} (1)

\dot E_{l} = \dot E_{in}-\dot E_{out} (2)

\dot E_{l} = \left(\frac{1}{\eta}-1\right)\cdot \dot E_{out} (3)

If we have the values of \eta = 0.91 and \dot E_{out} = 90\,hp, the heat supply rate can be calculated as:

\dot E_{l} = \left(\frac{1}{0.91}-1 \right)\cdot (90\,hp)

\dot E_{l} = 8.901\,hp

The heat supply rate amounts to 8.901 horsepower.

4 0
3 months ago
. A storm sewer is carrying snow melt containing 1.200 g/L of sodium chloride into a small stream. The stream has a naturally oc
Kisachek [356]

Answer:

Explanation:

In a steady-state condition, the total volume exiting matches the total volume entering, and

the total amount of salt entering equals the total amount of salt exiting.

The volume entering each minute is = 2000 + 2 x 10³ x 60

= 122000 L.

The total salt entering per minute = 1200 x 2000 + 20 x 2 x 10³ x 60

= 2400000 + 2400000 mg

= 4800000 mg.

The volume of water exiting each minute = 122000 L.

The total salt exiting each minute = 4800000 mg.

The concentration of salt in the exiting water = 4800000 / 122000

= 39.344 mg / L.

3 0
3 months ago
6.15. In an attempt to conserve water and to be awarded LEED (Leadership in Energy and Environmental Design) certification, a 20
Viktor [391]

Explanation:

At a temperature of 33^{\circ} C and relative humidity of 86%, the humidity ratio stands at 0.0223 with a specific volume of 14.289.

At a temperature of 33^{\circ} C and relative humidity of 40%, the humidity ratio is 0.0066 while the specific volume is 13.535.

To determine the mass of air, the following formula can be used:

\begin{aligned}m _{1} &=\frac{ v }{ v }(1- w ) \\&=\frac{1 \times 10^{5}}{13.535}(1-0.0066) \\&=7339.49 lb / min \\v _{ a } &=\frac{ m _{1} v }{(1- w )} \\v _{ a } &=\frac{7339.49 \times 14.289}{(1-0.0223)} \\v _{ a } &=107266.0 ft ^{3} / min\end{aligned}

Now, we will calculate the volume

\begin{aligned}m _{ w } &=\frac{ v _{ a }}{ v _{ a }} w _{ a }-\frac{ v _{ i }}{ v _{ i }} w _{ i } \\&=\frac{107266.0}{14.289} \times 0.0223-\frac{100000}{13.535} \times 0.0066 \\&=118.64 lb / min\end{aligned}

The duration required to fill the cistern can be determined with the equation:

Time \(=\frac{\text { cistern volume }}{\text { removal water perminute volume }}\)

By substituting the values into the preceding formula, we find:

\(\frac{\left(15 \times 10^{3} L\right) \times\left(0.0353147 ft ^{3} / L \right)}{(118.641 b / min ) \times\left(\frac{1}{62.41 lb / ft ^{3}}\right)}\)\\\(=279.09\) minutes\\\(=4.65\) hours.

Thus, the hours necessary to fill the cistern amount to 4.65 hours.

3 0
3 months ago
8. When supplying heated air for a building, one often chooses to mix in some fresh outside air with air that has been heated fr
pantera1 [306]
Refer to the explanation for a detailed breakdown.
5 0
2 months ago
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