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yarga
11 days ago
5

A pair of spur gears with 20 degree pressure angle, full-depth, involute teeth transmits 65 hp. The pinion is mounted on a shaft

connected to a 4 cylinder diesel engine that operates at 1250 rpm in the clockwise direction. The pinion has 26 teeth and a diameteral pitch of 6. The gear has 48 teeth and drives a concrete mixer. The gears are manufactured to an AGMA quality number of A11. The face width of the gears is 3 inches and are machined from solid bar stock (blanks). The gears are enclosed in a commercial gear box.
1. What is the pitch line speed of the gear train in feet per minute?
2. What is the center distance of the gear pair in inches?
3. What is the torque on the pinion in Lbin?
4. What is the torque on the gear in lbin?
5. What is the output horsepower of the gearbox?
6. What is the tangential force acting on the gear teeth (Wt) in pounds?
7. What is the radial force acting on the gear teeth in pounds?
8. What is the normal force acting on the gear teeth in pounds?
9. What is the bending stress for the pinion teeth (St) in PSI ?
Engineering
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A copper-constantan thermocouple is to be used to measure temperatures between 0 and 200°C. The e.m.f. at 0°C is 0 mV, at 100°C
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2 months ago
An AM radio transmitter operating at 3.9 MHz is modulated by frequencies up to 4 kHz. What are the maximum upper and lower side
Mrrafil [318]

Answer:

Total bandwidth: 8 kHz

Explanation:

Data provided:

Transmitter frequency: 3.9 MHz

Modulation up to: 4 kHz

Solution:

For the upper side frequencies:

Upper side frequencies = 3.9 × 10^{6} + 4 × 10³

Upper side frequencies = 3.904 MHz

For the lower side frequencies:

Lower side frequencies = 3.9 × 10^{6} - 4 × 10³

Lower side frequencies = 3.896 MHz

Consequently, the total bandwidth is computed as:

Total bandwidth = upper side frequencies - lower side frequencies

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6 0
3 months ago
A hydrogen-filled balloon to be used in high altitude atmosphere studies will eventually be 100 ft in diameter. At 150,000 ft, t
mote1985 [299]

Answer:

The calculated result is 11.7 ft

Explanation:

You can apply the combined gas law, which incorporates Boyle's law, Charles's law, and Gay-Lussac's Law, because hydrogen demonstrates ideal gas behavior under these specific conditions.

\frac{p_1 V_1}{T_1} = \frac{p_2 V_2}{T_2}

where the subscripts indicate "p" for pressure, "V" for volume, and "T" for temperature (in Kelvin) at varying moments. Let's denote t_1 as the balloon at 150,000 ft so

p_1 = 0.14 \ lb/in^2

V_1 = \frac{4}{3} \pi R_1^3 = 523598.77 \ ft^3

and T_1 = -67^\circ F = 218.15\ K.

Then t_2 represents the point at which the balloon is on the ground.

p_2 = 14.7 \ lb/in^2 and T_2 = 68^\circ F = 293.15\ K.

Based on the first equation

V_2 = \frac{p_1 V_1 T_2}{T_1 p_2}, we find

V_2 = 6701.07 ft^3 and consequently the radius turns out to be

R_2 = \sqrt[3]{\frac{3 V_2}{4 \pi}} = 11.7 \ ft.

5 0
2 months ago
Helium gas is compressed from 90 kPa and 30oC to 450 kPa in a reversible, adiabatic process. Determine the final temperature and
choli [298]

Answer:

T2 ( final temperature ) = 576.9 K

a) 853.4 kJ/kg

b) 1422.3 kJ / kg

Explanation:

given data:

pressure ( P1 ) = 90 kPa

Temperature ( T1 ) = 30°c + 273 = 303 k

P2 = 450 kPa

To determine final temperature in an Isentropic process

T2 = T1 (\frac{p2}{p1} )^{(k-1)/k} ----------- ( 1 )

T2 = 303 ( \frac{450}{90})^{(1.667- 1)/1.667} = 576.9K

The work performed in a piston-cylinder device is calculated using the subsequent formula

w_{in} = c_{v} ( T2 - T1 )    ------- ( 2 )

where: cv = 3.1156 kJ/kg.k for helium gas

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substituting values into equation 2

w_{in} = 853.4 kJ/kg

the work done in a steady flow compressor is determined using this

w_{in} = c_{p} ( T2 - T1 )

where: cp ( constant pressure of helium gas ) = 5.1926 kJ/kg.K

             T2 = 576.9 k, T1 = 303 K

plugging values back into equation 3

w_{in} = 1422.3 kJ / kg

4 0
2 months ago
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