Answer:
h = 12.8 cm
Explanation:
The initial parameters are as follows:
distance = 6.4 cm
- when the object descends, its weight matches the spring's force
weight = spring force
mg = ky... equation 1
- potential energy stored in a stretched spring = work done by the spring
mgh = 0.5 x k x h^{2}....equation 2
- Substituting from equation 1 into equation 2
kyh = 0.5 x k x h^{2}
y = 0.5 x h
2y = h
- where y is 6.4, yielding the maximum elongation as
h = 2 x 6.4 = 12.8 cm
Answer:
Explanation:
Amount of gold deposited = 0.5 g
Gold's molar mass = 197 g/mol
Time duration, t = 6 hours
= 6 × 3600
= 12600 s
Calculation of moles: mass/molar mass
= 0.5/197
= 0.00254 mole
Assuming
Au --> Au+ + e-
Faraday's constant = 9.65 x 10^4 C mol-1
Charge, Q = 96500 × 0.00254
= 244.924 C
Relation: Q = I × t
Thus, I = 244.924/12600
= 0.011 A
= 11.34 mA.
