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azamat
19 days ago
12

Determine the transition length at the entrance to a 10 mm tube through which 100 percent glycerol at 60 C is flowing at a veloc

ity of 0.5 m/s. The density of a glycerol is 1240 kg/m Data: The dynamic viscosity is 0.0813 Pa-s. a) 18.13 mm b) 50 mm c) 45.43 mm d) 38.13 mm
Chemistry
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How many moles are there in 2.00x10^19 molecules of CCl4?
eduard [2782]

Answer:

Explanation:

A mole is defined as the number of molecules divided by 6.02×10^23

Mole = (2×10^19)/(6.02×10^23)

Mole = 3.32×10^-5 mole

7 0
3 months ago
Which of the following air pollutants is correctly paired with one of its major effects?
alisha [2963]

Response:

The accurate choice is;

Sulfur oxides linked to acid precipitation

Details:

Sulfur oxide in the atmosphere interacts with oxygen, water, and other chemicals leading to the creation of acidic precipitation known as acid rain.

Sulfur oxides react with moisture in clouds to generate sulfuric acid as follows;

The sulfur gas undergoes initial oxidation

SO₂ + OH → HOSO₂

The subsequent step involves producing sulfur trioxide

HOSO₂ + O₂ → HO₂ + SO₃

Finally, sulfur trioxide reacts with water to yield sulfuric acid

SO₃ + H₂O → H₂SO₄ (aq).


3 0
3 months ago
In a hospital laboratory, a 10.0 mL sample of gastric juice (predominantly HCl), obtained several hours after a meal, was titrat
alisha [2963]

Answer: 1.14

Explanation:

HCl+NaOH\rightarrow NaCl+H_2O

To find the molarity of the acid, we will utilize the equation derived from the neutralization process:

n_1M_1V_1=n_2M_2V_2

where

are the n-factor, molarity, and volume for the acid and

represent the n-factor, molarity, and volume for NaOH.

We know that:n_1,M_1\text{ and }V_1HCl

By substituting the known values into the equation, we get:

n_1=1\\M_1=?\\V_1=10.0mL\\n_2=1\\M_2=0.1M\\V_2=7.2mL

To determine the pH of gastric juice:

The molarity amounts to = 0.072

1\times M_1\times 10.0=1\times 0.1\times 7.2\\\\M_1=0.072M

Thus, the pH level of the gastric juice is 1.14

3 0
3 months ago
what is the net ionic equation with its physical states? (NH4)2CO3(aq)+Ca(ClO4)2(aq)⟶CaCO3(s)+2NH4ClO4(aq)
lions [2927]

Answer: The net ionic equation is CO_3^{2-}(aq)+Ca^{2+}(aq)\rightarrow CaCO_3(s)

Explanation:

A double displacement reaction involves the exchange of ions. Chemicals that dissolve in water are marked with the symbol (aq), while those that do not dissolve and remain solid are shown with (s) after their formulas.

(NH_4)_2CO_3(aq)+Ca(ClO_4)_2(aq)\rightarrow CaCO_3(s)+2NH_4ClO_4(aq)

The ion-based representation of the equation is:

2NH_4^+(aq)+CO_3^{2-}(aq)+Ca^{2+}(aq)+2ClO_4^{-}(aq)\rightarrow CaCO_3(s)+2NH_4^{+}(aq)+2ClO_4^-(aq)

"Spectator ions" are the ions that do not participate in the chemical reaction, appearing on both sides of the equation in ionic form.

Ammonium and chlorate ions are present on both sides; thus, they do not factor into the net ionic equation.

Therefore, the net ionic equation is:

CO_3^{2-}(aq)+Ca^{2+}(aq)\rightarrow CaCO_3(s)

6 0
3 months ago
One hour of bicycle riding can require 500-900 kcal of energy, depending on the speed, the terrain, and the weight of the racer.
alisha [2963]
145 hours. Explanation: Riding a bicycle for one hour expends 505 kcal of energy. Given that one gram of body fat equals 7.70 kcal, and 1 pound of body fat is equivalent to 454 grams: 1 lb = 454 g; thus, 21 lb = 21 × 454/1 = 9534 g. Moreover, converting 9534 g of body fat gives us 9534 × 7.70 kcal/1 = 73411.8 kcal. If riding for one hour burns 505 kcal, then to lose 73411.8 kcal, it would require 73411.8 kcal x 1 hour/505 kcal = 145 hours.
3 0
2 months ago
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