Answer:
Explanation:
A mole is defined as the number of molecules divided by 6.02×10^23
Mole = (2×10^19)/(6.02×10^23)
Mole = 3.32×10^-5 mole
Response:
The accurate choice is;
Sulfur oxides linked to acid precipitation
Details:
Sulfur oxide in the atmosphere interacts with oxygen, water, and other chemicals leading to the creation of acidic precipitation known as acid rain.
Sulfur oxides react with moisture in clouds to generate sulfuric acid as follows;
The sulfur gas undergoes initial oxidation
SO₂ + OH → HOSO₂
The subsequent step involves producing sulfur trioxide
HOSO₂ + O₂ → HO₂ + SO₃
Finally, sulfur trioxide reacts with water to yield sulfuric acid
SO₃ + H₂O → H₂SO₄ (aq).
Answer: 1.14
Explanation:

To find the molarity of the acid, we will utilize the equation derived from the neutralization process:

where
are the n-factor, molarity, and volume for the acid and
represent the n-factor, molarity, and volume for NaOH.
We know that:

By substituting the known values into the equation, we get:

To determine the pH of gastric juice:
The molarity amounts to = 0.072

Thus, the pH level of the gastric juice is 1.14
Answer: The net ionic equation is 
Explanation:
A double displacement reaction involves the exchange of ions. Chemicals that dissolve in water are marked with the symbol (aq), while those that do not dissolve and remain solid are shown with (s) after their formulas.

The ion-based representation of the equation is:

"Spectator ions" are the ions that do not participate in the chemical reaction, appearing on both sides of the equation in ionic form.
Ammonium and chlorate ions are present on both sides; thus, they do not factor into the net ionic equation.
Therefore, the net ionic equation is:

145 hours.
Explanation: Riding a bicycle for one hour expends 505 kcal of energy. Given that one gram of body fat equals 7.70 kcal, and 1 pound of body fat is equivalent to 454 grams:
1 lb = 454 g; thus, 21 lb = 21 × 454/1 = 9534 g. Moreover, converting 9534 g of body fat gives us 9534 × 7.70 kcal/1 = 73411.8 kcal. If riding for one hour burns 505 kcal, then to lose 73411.8 kcal, it would require 73411.8 kcal x 1 hour/505 kcal = 145 hours.