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Jobisdone
11 days ago
13

In a hospital laboratory, a 10.0 mL sample of gastric juice (predominantly HCl), obtained several hours after a meal, was titrat

ed with 0.1 M NaOH to neutrality; 7.2 mL of NaOH was required. The patient’s stomach contained no ingested food or drink, thus assume that no buffers were present. What was the pH of the gastric juice?
Chemistry
1 answer:
alisha [2.7K]11 days ago
3 0

Answer: 1.14

Explanation:

HCl+NaOH\rightarrow NaCl+H_2O

To find the molarity of the acid, we will utilize the equation derived from the neutralization process:

n_1M_1V_1=n_2M_2V_2

where

are the n-factor, molarity, and volume for the acid and

represent the n-factor, molarity, and volume for NaOH.

We know that:n_1,M_1\text{ and }V_1HCl

By substituting the known values into the equation, we get:

n_1=1\\M_1=?\\V_1=10.0mL\\n_2=1\\M_2=0.1M\\V_2=7.2mL

To determine the pH of gastric juice:

The molarity amounts to = 0.072

1\times M_1\times 10.0=1\times 0.1\times 7.2\\\\M_1=0.072M

Thus, the pH level of the gastric juice is 1.14

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Answer:

The right responses are "bulb or pump; meniscus; outside".

Explanation:

Pipets are essential tools in laboratory settings. They are designed for transferring liquids from one vessel to another. First, a bulb or pump is attached to the top to empty the pipet completely. Next, fill the pipet until the meniscus (the curved top of the liquid) aligns with the measurement line corresponding to the volume needed. Finally, dispense the liquid into a second container and make sure to eliminate the last drop beyond the pipet tip.

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1 month ago
Every single-celled organism is able to survive because it carries out *
castortr0y [2743]

Every unicellular organism prospers by executing metabolic activities.

Metabolic activities encompass the set of chemical reactions essential for sustaining life.

Explanation:

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6 0
1 month ago
An unknown element is found to have three naturally occurring isotopes with atomic masses of 35.9675 (0.337%), 37.9627 (0.063%)
Tems11 [2403]

Answer:

The correct choice for your inquiry is option A, Argon.

Explanation:

Isotope               Atomic mass                      Percent (%)

    1                       35.9675                              0.337

    2                      37.9627                              0.063

    3                      39.9624                            99.6

To calculate the average atomic mass: (Mass of isotope 1)(percent of 1) + (Mass of isotope 2)(percent of 2) + (Mass of isotope 3)(percent of 3)

Average atomic mass = (35.9675)(0.00337) + (37.9627)(0.00063) + (39.9624)(0.996)

Average atomic mass = 0.1212 + 0.0239 + 39.8025

Average atomic mass = 39.9476

                   Theoretical  Atomic mass

a) Ar                         39.95

b) K                          39.10

c) Cl                         35.45

d) Ca                       40.08

                 

5 0
26 days ago
In basic solution, se2− and so32− ions react spontaneously and e o cell = 0.35 v. (a) write the balanced half-reactions for this
lions [2653]

(a)   Write the balanced half-reactions for the overall process:

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(b)   Assuming E sulfite is 0.57 V, compute E selenium:

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3 0
21 day ago
Marianne designs an experiment involving electrically charged objects. She wants to know which objects will be attracted to a ne
castortr0y [2743]

Answer:

The generation of static electricity occurs when two surfaces are rubbed together. This process causes a transfer of electrons, resulting in a build-up of negative charge. For instance, when you shuffle on a carpet, the friction creates multiple contact points which allow electrons to move onto you, thus accumulating a static charge. Touching another individual or object can lead to a sudden discharge, experienced as an electric shock.

In a similar way, rubbing a balloon against your hair generates opposite static charges on both your hair and the balloon. As you gently pull the balloon away from your head, the attraction between these opposite charges can be observed, causing your hair to rise.

Materials

• Balloon

• Woolen item (like a sweater, scarf, or yarn ball)

• Stopwatch

• Wall

• Partner (optional)

Preparation

• Inflate the balloon and secure the end.

• Have your partner ready to time with the stopwatch.

Procedure

• Grip the balloon with minimal hand coverage, such as holding it with just your thumb and index finger, or by its tied neck.

• Rub the balloon on the wool item once, making sure to go in one direction only.

• Press the rubbed side of the balloon against the wall and let go. Is it adhering to the wall? If it's stuck, your partner should start the stopwatch to measure how long it stays there. If it doesn’t stick, continue to the next step.

• Briefly touch the balloon to a metal object. Why is this step necessary?

• Repeat this procedure, but each time increase the number of rubs against the woolly item, ensuring the direction remains the same (do not rub back and forth).

Observations and results

As you increase the number of times you rub the balloon on the woolly material, does the duration of its adhesion to the wall increase?

Wool is an excellent conductor; it easily relinquishes electrons. When you rub wool on a balloon, electrons move from the wool to the surface of the balloon, imparting a negative charge to the rubbed area. Balloons, made from rubber, act as insulators, which means not all areas of the balloon will have a negative charge—only where it was rubbed will have a negative charge, while the rest of the balloon remains neutral.

Once the balloon is sufficiently charged negatively by repeated rubbing, it will adhere to the wall. Though the wall typically has a neutral charge, its internal charges can realign such that a positively charged region can attract the negatively charged balloon. Since the wall is also an insulator, the charge does not dissipate instantly. However, when the balloon is in contact with a metal object, the excess electrons from the balloon flow into the metal quickly, making the balloon lose its attraction and peel away.

HOPE IT HELPS

PLEASE MARK ME BRAINLIEST

6 0
1 month ago
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