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Jobisdone
2 months ago
13

In a hospital laboratory, a 10.0 mL sample of gastric juice (predominantly HCl), obtained several hours after a meal, was titrat

ed with 0.1 M NaOH to neutrality; 7.2 mL of NaOH was required. The patient’s stomach contained no ingested food or drink, thus assume that no buffers were present. What was the pH of the gastric juice?
Chemistry
1 answer:
alisha [2.9K]2 months ago
3 0

Answer: 1.14

Explanation:

HCl+NaOH\rightarrow NaCl+H_2O

To find the molarity of the acid, we will utilize the equation derived from the neutralization process:

n_1M_1V_1=n_2M_2V_2

where

are the n-factor, molarity, and volume for the acid and

represent the n-factor, molarity, and volume for NaOH.

We know that:n_1,M_1\text{ and }V_1HCl

By substituting the known values into the equation, we get:

n_1=1\\M_1=?\\V_1=10.0mL\\n_2=1\\M_2=0.1M\\V_2=7.2mL

To determine the pH of gastric juice:

The molarity amounts to = 0.072

1\times M_1\times 10.0=1\times 0.1\times 7.2\\\\M_1=0.072M

Thus, the pH level of the gastric juice is 1.14

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4 0
2 months ago
The graph above shows the changes in temperature recorded for the 2.00 l of h2o surrounding a constant-volume container in which
Alekssandra [3086]

Answer:

25.2 kJ

Explanation:

The full question can be found in the image linked to this response.

It's important to highlight that the heat absorbed by the 2.00 L of water for increasing its temperature from the beginning to the end comes solely from the burning of benzoic acid, as there are no heat transfers to the container or the surroundings.

To find the heat released from benzoic acid combustion, we simply measure the heat needed to warm the water.

Q = mCΔT

To find the mass of the water,

Density = (mass)/(volume)

Mass = Density × volume

Density = 1 g/mL

Volume = 2.00 L = 2000 mL

Mass = 1 × 2000 = 2000 g

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ΔT = (final temperature) - (Initial temperature)

<pAccording to the graph,

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Hope this Helps!!!

6 0
2 months ago
From this list, choose all of the ionic compounds. Check all that apply. View Available Hint(s) Check all that apply. POCl3 KOCH
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Answer: KOCH_2CH_3, CH_3CH_2COONa, NaOH are all ionic compounds.

Explanation:

Ionic compounds form when one atom transfers its valence electrons to another atom, resulting in partial opposite charges on the participating atoms, which creates a strong attractive force between them.

An ionic bond is typically established between a metal and a non-metal.

For instance, KOCH_2CH_3, CH_3CH_2COONa, NaOH are all ionic compounds.

Conversely, a covalent compound arises through the sharing of electrons among the atoms involved, where generally a non-metal bonds with the same or another non-metal.

For example, POCl_{3}, SOCl_{2} etc are all covalent compounds.

Therefore, we can affirm that KOCH_2CH_3, [tex]CH_3CH_2COONa, NaOH are indeed ionic compounds.

4 0
2 months ago
What volume of 0.550 M KBr solution can you make from 100.0 mL of 2.50 M KBr?
castortr0y [3046]
M1V1 = M2V2
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From 100.0 mL of 2.50 M KBr, you can prepare 455 mL of 0.550 M solution.
5 0
3 months ago
Read 2 more answers
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