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Rama09
2 months ago
11

The enthalpy of formation of water is –285.8 kJ/mol. What can be inferred from this statement?

Chemistry
2 answers:
alisha [2.9K]2 months ago
4 0
A negative formation enthalpy indicates that the reaction releases heat during the process.
(C,)
VMariaS [2.9K]2 months ago
3 0

The negative formation enthalpy of water suggests that heat is released during this reaction.

Answer: Option C

Explanation:

Enthalpy quantifies the system's internal energy, considering pressure and volume. The enthalpy of formation measures the change in enthalpy when products are formed from their elements.

<pthe enthalpy="" of="" formation="" refers="" to="" the="">enthalpy change needed to create 1 mole of the product from its elemental constituents and can be either negative or positive. A negative enthalpy of formation signifies the release of heat during the process. </pthe>
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If the following elements were to form ions, they would attain the same number of electrons as which noble gas? As , Be , O , S
Alekssandra [3086]

Answer;

As and Sr ------- [Kr]

Be ------------- [He]

O and Mg ------- [Ne]

S and Ca ------- [Ar]

Explanation

  • The Be+ ion has 2 electrons, matching He. The Mg2+ and O2− ions possess 10 electrons each, like Ne.
  • S2− and Ca2+ ions each have 18 electrons, the same as Ar. The As3− and Sr+ ions hold 36 electrons, paralleling Kr.
  • Elements gain or lose electrons to reach a stable electron configuration akin to that of noble gases.
  • When atoms lose electrons, they form positive ions (cations), and when they gain electrons, they form negative ions (anions).
4 0
3 months ago
Read 2 more answers
Recall that your hypothesis is that these values are the fraction of atoms that are still radioactive after n half-life cycles.
Alekssandra [3086]

Answer: A= 0.5, B = 0.25, C = 0.125, D = 0.015625 and E = 0.00390625

Explanation:

The half-life of a substance refers to the duration it takes for that substance to decrease to half of its original quantity.

Here, n signifies the count of half-lives.

The remaining quantity of the substance after n half-lives can be determined using the formula provided, 0.5^{n}

When n = 1,

Fraction of substance remaining = 0.5¹ = 0.5.

This indicates that after the first half-life, the remaining quantity is half of the original amount.

Thus, we find A = 0.5

<pfor n="2," we="" calculate=""><pso after="" two="" half-lives="" the="" remaining="" quantity="" is="" of="" original=""><phence>B = 0.25 <pfor n="3," we="" have=""><pso after="" three="" half-lives="" the="" remaining="" amount="" is="" of="" original.=""><ptherefore we="" find="">C = 0.125<pfor n="6," we="" see="">

Thus, D = 0.015625

<pfor n="8," we="" calculate=""><pconsequently>E = 0.00390625

The calculated values for A, B, C, D, and E are 0.5, 0.25, 0.125, 0.015625, and 0.00390625 respectively.

</pconsequently></pfor></pfor></ptherefore></pso></pfor></phence></pso></pfor>
8 0
2 months ago
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Which changes occur when Pt2+ is reduced?
lions [2927]
The accurate answer is option 2. When Pt2+ undergoes reduction, it loses electrons, thus oxidizing itself. The oxidation state corresponds to the atom's charge. When an electron is added, the overall charge diminishes, which in turn reduces the oxidation number.
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1 month ago
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What is the maximum number of covalent bonds an element with atomic number 8 can make with hydrogen?
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The right answer is 2.
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