1) The buoyant force acting on an object submerged in a fluid can be described as:
where
indicates the fluid's density, 
represents the volume of the fluid displaced, and 
signifies the gravitational acceleration.
2) To determine the volume of the displaced fluid, we note that the titanium object is entirely submerged in the fluid (air), thus this volume matches the volume of 1 Kg of titanium, which has a density of
. Using the correlation between density, volume, and mass, we derive
3) We can now revisit the equation in step 1) to compute the buoyant force. Given that the air density is
, this provides us with
4) The weight of 1 Kg of titanium is:
Therefore, the buoyant force is negligible when compared to the weight.
where
2) To determine the volume of the displaced fluid, we note that the titanium object is entirely submerged in the fluid (air), thus this volume matches the volume of 1 Kg of titanium, which has a density of
3) We can now revisit the equation in step 1) to compute the buoyant force. Given that the air density is
4) The weight of 1 Kg of titanium is:
Therefore, the buoyant force is negligible when compared to the weight.