When air is forced into the open pipe,
L = 
where n represents any whole number such as 1,2,3,4, etc., and λ denotes the wavelength of the oscillation
This implies λ=
It is important to note that n=1 corresponds to the fundamental frequency, n=2 corresponds to the first harmonic, and so forth.
Thus, the third harmonic will be for n=4
With L=6m and n=4, solving for λ yields:
λ=
=3m
The connection between frequency (f), sound speed (c), and wavelength (λ) is given by:
c=f.λ or f= 
Therefore, f=

≈115 Hz