Answer:
Explanation:
Provided:
mass of the steel ball 
initial velocity of the ball 
Final velocity of the ball 
(moving upwards)
The impulse given is determined by the change in the momentum of the object.
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Thus, the magnitude of the Impulse is 4 N-s.
</ptherefore>
Answer:
0.000047N
Explanation:
We know that
intensity (I) = P/ A
Where
P= power
A= Area
Thus, the power absorbed can be calculated as:
Power = Intensity x Area
This equals = 1.4 x 10^3 x(10)
Thus,
14000 Watts = 14 kWatt
However, the radiation pressure can be defined as
time-averaged intensity divided by the speed of light in a vacuum
So,
P = (1.4 x 1000)/c
Also,
F= P x A
Thus,
((1.4 x 1000)/(3 x10^8)) x 10
This results in
=0.000046666N
Rounded to two significant figures gives us
=0.000047 N
Result: 168N
The calculation shows 16 - 10 equals 6
and 6 divided by 10 equals 0.6
. Therefore, F equals 280 multiplied by 0.6 equals 168.
B) 14.0 N
To address this inquiry, we need to evaluate the kinetic energy of the box before and after crossing the rough section. The kinetic energy is given by the formula:
E = 0.5 M V^2
where
E = Energy
M = Mass
V = velocity
Now, utilizing the known data, we compute the energy prior and post.
Before:
E = 0.5 M V^2
E = 0.5 * 13.5kg * (2.25 m/s)^2
E = 6.75 kg * 5.0625 m^2/s^2
E = 34.17188 kg*m^2/s^2 = 34.17188 joules
After:
E = 0.5 M V^2
E = 0.5 * 13.5kg * (1.2 m/s)^2
E = 6.75 kg * 1.44 m^2/s^2
E = 9.72 kg*m^2/s^2 = 9.72 Joules
Hence, the box consumed energy equal to 34.17188 J - 9.72 J = 24.451875 J over a length of 1.75 meters. Next, we will calculate the loss per meter by dividing the energy loss by the distance traversed.
24.451875 J / 1.75 m = 13.9725 J/m = 13.9725 N
When we round to one decimal point, we arrive at 14.0 N, which corresponds with option “B.”
