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romanna
16 days ago
8

2. Harry is pushing a car down a level road at 2.0 m/s with a force of 243 N. The total force

Physics
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-. What is the acceleration of 4 kg trolling bag pulled by a girl with a<br> force of 3 N?
inna [3103]

Answer:

Acceleration(a) = 0.75 m/s²

Explanation:

Given:

Force(F) = 3 N

Mass of object(m) = 4 kg

Find:

Acceleration(a)

Computation:

Force(F) = ma

3 = (4)(a)

Acceleration(a) = 3/4

Acceleration(a) = 0.75 m/s²

3 0
4 months ago
A negatively charged object is located in a region of space where the electric field is uniform and points due north. the object
serg [3582]
- The greatest potential energy increase occurs when the charge travels north. This happens because the charge is negative, which means it gains potential energy when moving in the same direction as the field (in contrast, a positive charge moving along the field loses potential energy, converting it to kinetic energy). The potential energy gained is calculated as the charge multiplied by the distance moved:
\Delta U = e d

- The next largest increase occurs as the charge moves east. Here, the change in potential energy is actually zero since the charge moves perpendicular to the field, traversing points with constant potential. Therefore, there is no variation in potential energy in this case:
\Delta U = 0

- Finally, when the charge moves south, it experiences a reduction in potential energy. This is due to moving against the electric field, and since it is a negative charge, it loses potential energy in this direction, which transforms into kinetic energy. Thus, in this scenario:
\Delta U = - e d
5 0
2 months ago
A copper sphere was moving at 25 m/s when it hit another object. This caused all of the KE to be converted into thermal energy f
kicyunya [3294]

Answer:

\Delta T = 0.81 ^oC

Explanation:

According to the principle of energy conservation

all kinetic energy will change into thermal energy to increase its temperature

\frac{1}{2}mv^2 = ms\Delta T

Next, divide both sides by the object's mass

\frac{1}{2}v^2 = s\Delta T

the resulting temperature change is expressed as

\Delta T = \frac{v^2}{2s}

\Delta T = \frac{25^2}{2\times 387}

\Delta T = 0.81^oC

3 0
3 months ago
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