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Zanzabum
14 days ago
10

-. What is the acceleration of 4 kg trolling bag pulled by a girl with a force of 3 N?

Physics
1 answer:
inna [987]14 days ago
3 0

Answer:

Acceleration(a) = 0.75 m/s²

Explanation:

Given:

Force(F) = 3 N

Mass of object(m) = 4 kg

Find:

Acceleration(a)

Computation:

Force(F) = ma

3 = (4)(a)

Acceleration(a) = 3/4

Acceleration(a) = 0.75 m/s²

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Is the electric potential energy of a particle with charge q the same at all points on an equipotential surface?
Sav [1095]
Indeed. This is the reason it's termed equipotential. 
8 0
4 days ago
A roller coaster, traveling with an initial speed of 15 meters per second, decelerates uniformly at â7.0 meters per second2 to a
Keith_Richards [1021]
<span>We can deduce distance using the equation d = [(v_f^2) - (v_i^2)]/(2a). So, d = [(0^2)-(15^2)]/(2*-7) d = [0-(225)]/(-14) d = 225/14 d = 16.0714 m Considering two significant figures, the roller coaster covers approximately 16 meters as it decelerates.</span>
8 0
11 days ago
A convex mirror with a focal length of 0.25 m forms a 0.080 m tall image of an automobile at a distance of 0.24 m behind the mir
ValentinkaMS [1144]

Answer:

The object measures 6 m in distance and 2 m in height.

It creates a virtual image that is upright.

Explanation:

Provided data includes:

Focal length = 0.25 m

Image height = 0.080 m

Image distance = 0.24 m

We are to determine the object's distance.

Using the lens formula:

\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}

Substituting values into the formula:

\dfrac{1}{0.24}=\dfrac{1}{0.25}+\dfrac{1}{u}

\dfrac{1}{u}=\dfrac{1}{0.24}-\dfrac{1}{0.25}

\dfrac{1}{u}=\dfrac{1}{6}

u=6\ m

We also need to calculate magnification:

Applying the magnification formula:

m=-\dfrac{v}{u}

Substituting values into this formula:

m=-\dfrac{0.24}{-6}

m=0.04

Next, we need to find the height of the object:

Using the magnification formula once more:

m=\dfrac{h'}{h}

h=\dfrac{0.080}{0.04}

h=2\ m

A convex mirror generates a virtual and upright image on its backside.

Consequently, the object is at a distance of 6 m and has a height of 2 m.

The image formed is virtual and upright.

6 0
6 days ago
Read 2 more answers
A fox locates rodents under the snow by the slight sounds they make. The fox then leaps straight into the air and burrows its no
Ostrovityanka [942]

Response:

v = 4.08 m/s²

Clarification:

4 0
7 days ago
The magnitude of the Poynting vector of a planar electromagnetic wave has an average value of 0.939 W/m2. The wave is incident u
Yuliya22 [1153]

Answer:

The total energy can be expressed as T = 169.02 \ J

Explanation:

The problem states that

The Poynting vector, which measures energy flux, equals k = 0.939 \ W/m^2

The rectangle's length is represented by l = 1.5 \ m

The width of the rectangle is w = 2.0 \ m

The duration considered is t = 1 \ minute = 60 \ s

Mathematically, the overall electromagnetic energy incident on the area is given by

T = k * A * t

where A denotes the area of the rectangle, calculated as

A= l * w

By plugging in the respective values

A= 2 * 1.5

A= 3 \ m^2

Again substituting values

T = 0.939 * 3 * 60

T = 169.02 \ J

5 0
6 days ago
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