Answer:
The accurate statements are
2. The train is not an inertial frame of reference.
5. The train could be moving at a constant velocity in a circular path.
8. The train must be undergoing acceleration.
Explanation:
As we observe that the string forms an angle with the horizontal
we can formulate the force equation relevant to the given ball
similarly in the Y direction
Thus we conclude
In the query, it is stated that
The intensity of the uniform electric field equals The distance the electron covers is
Typically, the force exerted on this electron is expressed mathematically as
Where F signifies the force and q represents the charge of the electron, which is a fixed value of
Thus
Generally, the work-energy theorem is mathematically framed as
Where W denotes the work done on the electron by the electric field and is the change in kinetic energy
Additionally, work done on the electron can also be described as
Where assuming that the electron's movement aligns with the x-axis
So
Inserting values
According to the conservation of energy
Where signifies the change in potential energy
Thus
Answer:
a) τ = i ^ (y - z
) + j ^ (z Fₓ - x
) + k ^ (x
- y Fₓ)
b) τ = (-0.189i ^ -5.6 j ^ + 33.978k ^) N m
c) α = (-7.8 10⁻⁴ i ^ - 2.3 10⁻² j ^ + 1.4 10⁻¹ k ^) rad / s²
Explanation:
a) The torque can be expressed as
τ = r x F
To tackle this equation, using the determinant approach is the most straightforward method
The resulting expression is
τ = i ^ (y - z
) + j ^ (z Fₓ - x
) + k ^ (x
- y Fₓ)
b) Now let's compute
τ = i ^ (0.075 1.4 -0.035 8.4) + j ^ (0.035 2.8 - 4.07 1.4) + k ^ (4.07 8.4 - 0.075 2.8)
τ = i ^ (- 0.189) + j ^ (-5.6) + k ^ (33,978)
τ = (-0.189i ^ -5.6 j ^ + 33.978k ^) N m
c) To find angular acceleration, we use
τ = I α
α = τ / I
The moment of inertia being a scalar means that only the magnitude of each component changes, orientation remains constant.
α = (-0.189i^ -5.6 j^ + 33.978k^) / 241
α = (-7.8 10⁻⁴ i ^ - 2.3 10⁻² j ^ + 1.4 10⁻¹ k ^) rad / s²