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ICE Princess25
12 days ago
7

A copper sphere was moving at 25 m/s when it hit another object. This caused all of the KE to be converted into thermal energy f

or the copper sphere. If the specific heat capacity of copper is 387 J/(kg ⋅ C°), what was the increase in temperature?
0.23 C°
0.81 C°
1.3 C°
2.1 C°
Physics
1 answer:
kicyunya [2.2K]12 days ago
3 0

Answer:

\Delta T = 0.81 ^oC

Explanation:

According to the principle of energy conservation

all kinetic energy will change into thermal energy to increase its temperature

\frac{1}{2}mv^2 = ms\Delta T

Next, divide both sides by the object's mass

\frac{1}{2}v^2 = s\Delta T

the resulting temperature change is expressed as

\Delta T = \frac{v^2}{2s}

\Delta T = \frac{25^2}{2\times 387}

\Delta T = 0.81^oC

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A ball rolls up a slope. At the end of three seconds its velocity is 20 cm/s; at the end of eight seconds its velocity is 0. Wha
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Answer:

a_{acceleriation}=-4cm/s^{2}\\ or\\ a_{acceleriation}=-0.04m/s^{2}

Explanation:

Data provided

initial velocity v₀=20 cm/s at time t=3s

final velocity vf=0 at time t=8 s

Required

Average Acceleration for the interval from 3s to 8s

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If white wool (W) is dominant over black wool (w), can two sheep with white wool produce an offspring with black wool? Explain y
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The iron ball shown is being swung in a vertical circle at the end of a 0.7-m string. how slowly can the ball go through its top
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An object initially at rest experiences a constant horizontal acceleration due to the action of a resultant force applied for 10
inna [2205]

Answer:

a = 18.28 ft/s²

Explanation:

the values provided are:

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So,

the work is equivalent to the change in kinetic energy

W = \dfrac{1}{2} m (v_f^2-v_i^2)

7781.5 = \dfrac{1}{2}\times 0.466\times v_f^2

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The acceleration of the object is therefore

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the constant acceleration of the object is calculated to be 18.28 ft/s²

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25 days ago
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