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Illusion
17 days ago
12

Bradley and 23 of his classmates went on a trip to the aquarium. There are 8 more boys than girls on the trip. Write a system of

equations to model the problem. Then solve the system algebraically. How many boys and girls were on the trip?
Mathematics
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A pineapple is 7 times as heavy as an orange. the pineapple also weighs 870 grams more than the orange. what is the total weight
zzz [12365]
Let's convert each statement into mathematical terms.

Pineapple = p

Orange = x

is indicates equality

 

Pineapple has a weight that is 7 times that of an orange:  p = 7x

Pineapple is 870 grams heavier than the orange. p = 870 + x

 

Insert  p = 7x  into the second equation:

7x = 870 + x

Subtract  x from both sides

6x = 870

Divide by 6

x = 145

 

The weight of the orange is 145 grams.

The weight of the pineapple is 7 times that of the orange = 7(145) = 1015 grams.

4 0
2 months ago
Many gas stations give a discount for using cash instead of a credit card. A gas station gives a discount of 10 cents per gallon
babunello [11817]

Response:

2.33 $

Detailed breakdown:

10x14=140 cents / 2.33$

4 0
3 months ago
A certain pen has been designed so that true average writing lifetime under controlled conditions (involving the use of awriting
tester [12383]

Answer:

a) Null hypothesis:\mu \geq 10

Alternative hypothesis:\mu < 10

b) p_v =P(t_{17}

Given that the p-value is lower than the significance threshold in this situation, we have sufficient grounds to reject the null hypothesis.

c) p_v =P(t_{17}

In this case, since the p-value exceeds the significance threshold, we have adequate evidence to FAIL to reject the null hypothesis.

d) p_v =P(t_{17}

Here again, with the p-value being less than the significance level, we can reject the null hypothesis.

Step-by-step explanation:

1) Provided data and references

\bar X represents the average of the samples

s denotes the standard deviation of the samples

n=18 indicates the number of samples

\mu_o =10 is the value we are examining

\alpha defines the significance level for the test.

t represents the specific statistic of interest

p_v indicates the p-value relevant to the test (the variable of concern)

Define the null and alternative hypotheses.

To assess if the true mean is at least 10 hours, we must set up a hypothesis:

Part a

Null hypothesis:\mu \geq 10

Alternative hypothesis:\mu < 10

If we consider the sample size being less than 30 and the population deviation unknown, it’s more appropriate to use a t-test to compare the actual mean with the reference value, calculated as:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)

Part b

In this scenario t=-2.3, \alpha=0.05

Initially, we need to calculate the degrees of freedom df=n-1=18-1=17

Since this is a left-tailed test, the p-value is determined by:

p_v =P(t_{17}

In this instance, with the p-value being less than the significance level, we have sufficient evidence to reject the null hypothesis.

Part c

For this situation t=-1.8, \alpha=0.01

We need to find the degrees of freedom df=n-1=18-1=17

For the left-tailed test, the p-value is given by:

p_v =P(t_{17}

In this case, since the p-value is above the significance level, we have enough grounds to FAIL to reject the null hypothesis.

Part d

For this case t=-3.6, \alpha=0.05

Firstly, we find the degrees of freedom df=n-1=18-1=17

Since we are conducting a left-tailed test, the p-value is calculated as:

p_v =P(t_{17}

Here, with the p-value being lower than the significance threshold, we can reject the null hypothesis.

5 0
3 months ago
The bus routes in a city run on average every 15 minutes. The route times can vary by three minutes. Which absolute value equati
AnnZ [12381]

Response:

Max = 18\ mins

Min = 12\ mins

Step-by-step explanation:

Information given:

Time = 15\ mins

Variation = 3\ mins

Objective:

Calculate the maximum and minimum values

The max value is found as follows:

Max = Time + Variation

Max = 15\ mins + 3\ mins

Max = 18\ mins

The min value is identified as follows:

Min = Time - Variation

Min = 15\ mins - 3\ mins

Min = 12\ mins

3 0
4 months ago
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