Answer:
2.55 cubic meters of sand
Step-by-step explanation:
The inquiry focuses on how much sand is needed to completely fill the sandbox. As it is a three-dimensional shape, the concept of 'Volume' is applicable. Volume is determined through the formula L × W × H. By substituting the relevant variables into this equation, you arrive at the final solution. I hope this offers clarity!
To calculate this, a specific formula will be necessary. Years = log (total/principal) / [n * log (1 + rate / n)]. Part A) For Calvin: $400 at 5% monthly results in $658.80; Time =? Monthly compounding, n = 12. Thus, Years = log(658.80/400) / [12 * log(1+ (.05/12))]. Subsequently, Years = log(
1.647) / (12 * log(1.0041666667)). Then, Years = 0.21669359917 / 12 * 0.0018058008777. Thus resulting in Years = 0.21669359917 / 0.0216696105. Ultimately, Years ≈ 9.999884362. Part B) For Makayla: $300 at 6% quarterly yields $613.04; Time=? Quarterly compounding, n = 4. Therefore, Years = log(613.04/300) / [4 * log (1 +.06/4)]. This results in Years = log(2.0434666667) / (4 * log(1.015)). Years thus equals 0.31036755784 / (4 * 0.0064660422492), resulting in Years ≈ 11.9999044949. The approximate difference is about 3 years.
Answer:
- 8
Step-by-step explanation:
Given the expression
(3x² - 5)(4 + 4x²)
Each term from the second factor is multiplied by every term in the first factor, meaning
3x²(4 + 4x²) - 5(4 + 4x²) ← distribute both parentheses
= 12x² + 12
- 20 - 20x² ← combine like terms
= 12 - 8x² - 20
The coefficient for the x² term is - 8
Answer:
Volume of the shaded area = (600 - 36π) units³
Step-by-step explanation:
Volume of the shaded area = Volume of pyramid - Volume of cone
Volume of pyramid = ⅓*l*w*h
Where,
l = length of the base of the pyramid = 15 units
w = width of the base of the pyramid = 10 units
h = height of pyramid = 12 units
Substituting the values helps find the volume of the pyramid
Volume of pyramid = ⅓*15*10*12 = 5*10*12 = 600 units³
Volume of Cone = ⅓πr²h,
Where,
r = radius = ½ of diameter = ½ of 9 = 3 units
h = height = 12 units
Volume of Cone = ⅓*π*3²*12 = ⅓*π*9*12
= π*3*12 = 36π units³
Volume of shaded area = (600 - 36π) units³
