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r-ruslan
16 days ago
8

The market price of a house is directly proportional to the total area of the house in square feet. If the price of a 1,500 squa

re foot home is $300,000 what is the price of a 2,000 square foot home?
Mathematics
1 answer:
zzz [4K]16 days ago
5 0

Answer:

The cost for a 2,000 square foot house is \$400,000

Detailed explanation:

Recall that if two variables x and y vary directly, the relationship can be written as y/x=k or y=kx.

Define:

x as the house area in square feet

y as the price of the house

Given point (1500, 300000)

Calculate proportionality constant k:

k=y/x

Insert values:

k=300,000/1,500=200

The direct variation equation is:

y=200x

For x = 2000:

Calculate y:

Replace x in equation:

y=200(2,000)

y=\$400,000

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This involves discovering the largest number that divides both 72 and 24 evenly,
which is known as the GCM or greatest common multiplier.

To determine the GCM, factor 72 into primes and group them:
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24=2 times 2 times 2 times 3
Thus, the common grouping is 2 times 2 times 2 times 3, equating to 24.
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For pencils:
72 divided by 24=3
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For calculators:
24 divided by 24=1
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12 days ago
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if a student scored 78 points on a test where the mean score was 84.5 and the standard deviation was 3.1. the student's z score
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Answer:

(value - mean)/standard deviation.

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Step-by-step explanation:

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2 days ago
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What other points are on the line of direct variation through (5, 12)? Check all that apply. (0, 0) (2.5, 6) (3, 10) (7.5, 18) (
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It is established that

A correlation between two variables, x and y, demonstrates a direct variation if it can be written in the format y/x=k or y=kx

For this question, we have

the point (5,12) lies on the direct variation line

therefore

Determine the constant of proportionality k

y/x=k-------> substitute ------> k=12/5

The equation is

y=\frac{12}{5}x

Keep in mind that

If a point is located on the direct variation line

then

the point has to fulfill the direct variation equation

we will now validate each point

case A) point (0,0)

x=0\ y=0

Insert the values of x and y into the direct variation equation

0=\frac{12}{5}*0

0=0 -------> is valid

thus

the point (0,0) lies on the direct variation line

case B) point (2.5,6)

x=2.5\ y=6

Insert the values of x and y into the direct variation equation

6=\frac{12}{5}*2.5

6=6 -------> is valid

thus

the point (2.5,6) lies on the direct variation line

case C) point (3,10)

x=3\ y=10

Insert the values of x and y into the direct variation equation

10=\frac{12}{5}*3

10=7.2 -------> is not valid

thus

the point (3,10) does not lie on the direct variation line

case D) point (7.5,18)

x=7.5\ y=18

Insert the values of x and y into the direct variation equation

18=\frac{12}{5}*7.5

18=18 -------> is valid

thus

the point (7.5,18) lies on the direct variation line

case E) point (12.5,24)

x=12.5\ y=24

Insert the values of x and y into the direct variation equation

24=\frac{12}{5}*12.5

18=30 -------> is not valid

thus

the point (12.5,24) does not lie on the direct variation line

case F) point (15,36)

x=15\ y=36

Insert the values of x and y into the direct variation equation

36=\frac{12}{5}*15

36=36 -------> is valid

thus

the point (15,36) lies on the direct variation line

ultimately

the solution is

(0,0)

(2.5,6)

(7.5,18)

(15,36)


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