First convert grams of C4H10 to moles using its molar mass of 58.1 g/mol:
3.50 g C4H10 × (1 mol C4H10 / 58.1 g C4H10) = 0.06024 mol C4H10
Next convert moles to molecules using Avogadro’s number:
0.06024 mol C4H10 × (6.022×10^23 molecules C4H10 / 1 mol C4H10) = 3.627×10^22 molecules C4H10
Each butane molecule contains 4 carbon atoms, so:
3.627×10^22 molecules C4H10 × (4 atoms C / 1 molecule C4H10) = 1.45×10^23 carbon atoms present.
Answer :
The percentage ionic character (%IC) equals 10%, indicating the bond is mostly covalent with slight polarity.
Percent Ionic Character:
This reflects the fraction of ionic nature within a polar covalent bond. The formula for %IC (% ionic character) is:

Here, Xa is the electronegativity of atom A and Xb is that of atom B.
Given: The compound is TiAl₃.
Electronegativity of Ti = 2.0
Electronegativity of Al = 1.6 (as shown in the provided image)
Substitute these values into the formula:



The value of e⁻¹ equals 0.90.
Therefore, percent ionic character = (1 - 0.90) × 100
Percent Ionic Character = 10%
Because the % IC is only 10%, which is relatively low, the bond is classified as covalent with minimal polarity.