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According to Arrhenius, bases are defined as substances that produce OH⁻ ions when they dissolve in water. The anion NO₂⁻ fits this definition as illustrated in the following reaction:
NO₂⁻(aq) + H₂O (l) HNO₂ (aq) + OH⁻(aq)
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Answer: Pentane C5H12
Explanation:
The boiling point is defined as the temperature at which a liquid's vapor pressure matches the external pressure, causing the liquid to turn into vapor.
This compound is likely Pentane, represented as C5H12, since its boiling point falls between that of Butane, with the formula C4H10, and Hexane, with the formula C6H14.
Response:
To reach the answer, 465.6 mg of MgI₂ is required.
Detailed Explanation:
We need to establish the moles of ion I⁻ in the resulting solution.
C = n/V -> n = C x V = 0.2577 (L) x 0.1 (mol/L) = 0.02577 mol.
In the initial solution, there was 0.087 M KI, which we can similarly convert into moles, yielding 0.02242 mol.
This indicates we require an additional amount of 0.02577 - 0.02242 = 0.00335 mol of I⁻. Since each molecule of MgI₂ produces two I⁻ ions, we divide 0.00335 by 2 to determine the moles of MgI₂, giving us 0.001675 mol.
Consequently, the quantity of MgI₂ to be added is:
Weight of MgI₂ = 0.001675 mol x 278 g/mol = 0.4656 g = 465.6 mg
Response:
K = 6.5 × 10⁻⁶
Detailed Explanation:
C₅H₆O₃ ⇄ C₂H₆ + 3CO
Apply PV=nRT to determine the initial pressure of C₅H₆O₃
P (2.50) = (0.0493) (0.08206) (473)
P = 0.78atm
C₅H₆O₃ ⇄ C₂H₆ + 3CO
0.78atm 0 0
0.78 - x x 3x
1.63atm = 0.78 - x + x + 3x
P(total) = 0.288atm
C₅H₆O₃ = 0.78 - 0.288
= 0.489atm
C₂H₆ = 0.288atm
CO = 0.846atm
= 0.379
= 6.5 × 10⁻⁶
