Answer:
The book is titled Solid State or Condensed Matter
Explanation:
Answer:
The water level increases more when the cube is above the raft before it sinks.
Explanation:
The principle involved is based on Archimedes' theory, which states that immersing an object in water will raise the initial water level. This means that the height of the water in the container increases. The increase in water volume corresponds to the volume of the submerged object.
We can consider two scenarios: when the steel cube rests on the raft and when it settles at the pool's bottom.
When the cube rests at the pool’s bottom, the volume will indeed rise, and we can ascertain this using the cube's volume.
Vc = 0.45*0.45*0.45 = 0.0911 [m^3]
When an object floats, it's because the densities of the object and water are in equilibrium.
![Ro_{H2O}=R_{c+r}\\where:\\Ro_{H2O}= water density = 1000 [kg/m^3]\\Ro_{c+r}= combined density cube + raft [kg/m^3]](https://tex.z-dn.net/?f=Ro_%7BH2O%7D%3DR_%7Bc%2Br%7D%5C%5Cwhere%3A%5C%5CRo_%7BH2O%7D%3D%20water%20density%20%3D%201000%20%5Bkg%2Fm%5E3%5D%5C%5CRo_%7Bc%2Br%7D%3D%20combined%20density%20cube%20%2B%20raft%20%5Bkg%2Fm%5E3%5D)
The formula for density is:
Ro = m/V
where:
m= mass [kg]
V = volume [m^3]
The buoyant force can be calculated with this equation:
![F_{B}=W=Ro_{H20}*g*Vs\\W = (200+730)*9.81\\W=9123.3[N]\\\\9123=1000*9.81*Vs\\Vs = 0.93 [m^3]](https://tex.z-dn.net/?f=F_%7BB%7D%3DW%3DRo_%7BH20%7D%2Ag%2AVs%5C%5CW%20%3D%20%28200%2B730%29%2A9.81%5C%5CW%3D9123.3%5BN%5D%5C%5C%5C%5C9123%3D1000%2A9.81%2AVs%5C%5CVs%20%3D%200.93%20%5Bm%5E3%5D)
Vs > Vc indicates that the combined volume of the raft and the cube exceeds that of the cube alone resting at the bottom of the pool. Hence, when the cube is positioned above the raft, the water level rises more before it becomes submerged.
1. Initially removing a strip leaves some electrons behind, resulting in the strip becoming positively charged. 2. The roll itself does not acquire a negative charge since it is grounded by the hand holding it, causing excess negatives to repel through the hand. 3. Tearing off another strip again leaves electrons behind, this new strip is also positively charged and will repel the first strip. 4. When two strips are then pulled apart, one will transfer electrons to the other, creating one positively charged strip and one negatively charged strip, which will attract each other.
A block weighing m1 = 4.50 kg and a ball weighing m2 = 7.70 kg are linked by a light string over a frictionless pulley, as illustrated in figure (a). The coefficient of kinetic friction between the block and the surface is 0.300.
(a) Determine the acceleration of both objects and the tension present in the string.
(b) Verify the acceleration calculation using a systems approach. (Utilize m1, m2, μk, and g as needed.)
(c) If an additional mass is added to the ball, what amount is necessary to augment the downward acceleration by 60%?
In (a), I calculated the acceleration to be 5.10 m/s^2 and the tension to be 36.2N.
In (b), the equation used is a = (m2g-ukm1g)/(m1+m2)
It’s (c) that I am struggling to understand. Can anyone assist me?