Answer:
F=126339.5N
Explanation:
To compute the force required to escape, a free-body diagram for the hatch must be drawn. We will equate the downward and upward forces, thus applying the following equation:
Fw=W+Fi+F
where
Fw= force or weight exerted by the water column above the submarine.
To calculate Fw, we can use:
Fw=h. γ. A
h=height
γ=
specific weight of seawater = 10074N / m ^ 3
A=Area
Fw=28x10074x0.7=197467N
w represents the hatch weight = 200N
Fi denotes the internal pressure force in the submarine, which is 1 atm = 101325Pa. We can calculate this force using:
Fi=PA=101325x0.7=70927.5N
Finally, the force needed to open the hatch is determined by the original equation:
Fw=W+Fi+F
F=Fw-W+Fi
F=197467N-200N-70927.5N
F=126339.5N
We know that F=ma
where m represents mass and a indicates acceleration
thus, Force= ma
therefore, F=1300X1.07=1391N
I hope this helps
if my answer assists you, please consider marking it as the best one
Answer:
Explicación:
Definamos v como la velocidad lineal, ω como la velocidad angular e I como el momento de inercia del disco.
La energía cinética (lineal) = 1/2 mv²
La energía cinética rotacional = 1/2 I ω²
I = 1/2 m r² (donde m y r son la masa y el radio del disco)
La energía cinética rotacional = 1/2 x1/2 m r² ω²
= 1/4 m v² (v = r ω)
Energía total
= Energía cinética (lineal) + Energía cinética rotacional
= 1/2 mv² + 1/4 mv²
= 3/4 mv²
La relación de K E rotacional / K E total = 1/4 m v² / 3/4 mv²
= 1 /3
Por lo tanto, 1 /3 de la energía total se debe a la energía cinética rotacional.
