Answer: damping coefficient = 1.5×10^5Ns/m
Explanation:
Refer to the attached file for the solution
Molybdenum (Mo) has a BCC crystal structure, an atomic radius of 0.1363 nm, and an atomic weight of 95.94 g/mol. Compute and com
2 answers:
Answer
The experimental value is 10.78 g/cm³
Explanation:
The density formula yields
In a BCC structure for Mo, there are 9 atoms, and the cell edge length (a) is twice the atomic radius (
r).
a = 9, r = 0.1363 nm = 1.363 A
Therefore, a = 2 × 9 r = 18r
The total volume of atoms = =
= 14, 767.434
The molar mass of Mo is 95.95 g/mol
Thus, the density can be calculated as ×
= 10.79E18
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Response:
Clarification:
We need an expression that shows how much water has been drained from the tub. This is represented by v, which indicates how many gallons have flowed out since the plug was taken out. Each gallon removed equates to 8.345 pounds of water, so the weight of the drained water Q in pounds as a function of v can be expressed as:
Where v signifies the number of gallons emptied from the tub.
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Answer:
B= ≅8.06
Explanation:
Applying the Pythagorean theorem:
=
+
Here, C denotes the hypotenuse length, while A and B signify the lengths of the other two sides of the triangle. We can calculate B's length knowing the hypotenuse is 9 and A is 4.
=
+
81= 16+
81-16=
B= ≅8.06