Molybdenum (Mo) has a BCC crystal structure, an atomic radius of 0.1363 nm, and an atomic weight of 95.94 g/mol. Compute and com
2 answers:
Answer
The experimental value is 10.78 g/cm³
Explanation:
The density formula yields
In a BCC structure for Mo, there are 9 atoms, and the cell edge length (a) is twice the atomic radius (
r).
a = 9, r = 0.1363 nm = 1.363 A
Therefore, a = 2 × 9 r = 18r
The total volume of atoms = =
= 14, 767.434
The molar mass of Mo is 95.95 g/mol
Thus, the density can be calculated as ×
= 10.79E18
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Answer:
The magnification is calculated to be 3
Explanation:
It has been provided that
The lens' focal length is f = 15 cm
The object distance is u = -10 cm
Using the lens formula:
v signifies image distance
Thus, the magnification of the lens is found to be 3.
Refer to the diagram below.
This discussion operates under a basic analysis that overlooks air resistance and variations in the terrain the missile traverses.
Let V₀ be the launch velocity, at an angle θ to the horizontal.
The horizontal velocity component equals V₀ cosθ.
If the flight duration is
, then
where r represents the missile's range.
The time t at which the missile is at ground level is expressed by
where g signifies acceleration due to gravity.
t = 0 signifies the missile's launch. Thus
Consequently,
Typically, an angle of θ=45° is optimal for achieving maximum range, resulting in
This discussion applies more accurately to a scud missile than to a powered, guided missile.
Response:
Usually, θ=45°
This discussion operates under a basic analysis that overlooks air resistance and variations in the terrain the missile traverses.
Let V₀ be the launch velocity, at an angle θ to the horizontal.
The horizontal velocity component equals V₀ cosθ.
If the flight duration is
where r represents the missile's range.
The time t at which the missile is at ground level is expressed by
where g signifies acceleration due to gravity.
t = 0 signifies the missile's launch. Thus
Consequently,
Typically, an angle of θ=45° is optimal for achieving maximum range, resulting in
This discussion applies more accurately to a scud missile than to a powered, guided missile.
Response:
Usually, θ=45°
The peak wavelength for Betelgeuse is 828 nm
Explanation:
Wien's law describes how the surface temperature relates to a star’s peak wavelength:
where
represents the peak wavelength
T is the surface temperature
is Wien's constant
For Betelgeuse, the surface temperature is roughly
T = 3500 K
Consequently, its peak wavelength can be determined as:
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