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Agata
7 days ago
6

Determine what type of model best fits the given situation a population of wolves is presently at 500 and is decreasing by 10% e

ach year.
A. Quadratic
B. Exponential
C. Linear
D. None of these
Mathematics
You might be interested in
SALES Cars and trucks are the most popular vehicles. Last year, the number of cars sold was 39,000 more than three times the num
PIT_PIT [12445]

Given :

Miki possesses 104 nickels and 88 dimes. She intends to sort her coins into sets where each set has an equal count of both nickels and dimes.

Last year, 216,000 cars were sold.

To Find :

An equation that can identify the number of trucks, t, sold the previous year.

Solution :

Let t represent the quantity of trucks sold and c represent the cars sold.

The statement indicates that the quantity of cars sold exceeded three times the trucks sold by 39,000.

Thus,

c=3t+39000\\\\t=\dfrac{c-39000}{3}

Plugging the value of c = 216000 into the equation above yields :

t=\dfrac{c-39000}{3}\\\\t=\dfrac{216000-39000}{3}\\\\t=59000

This gives us the solution we seek.

​

8 0
4 months ago
A statistics teacher was interested in the relationship between the number of days students waited to start a project and the sc
tester [12383]

Answer:

A: With each additional procrastination day, the expected grade drops by 3.64 points.

Step-by-step explanation:

The slope of a Regression Line

A linear equation can be expressed in slope-intercept form:

y = mx + b

Here, m represents the slope and b indicates the y-intercept.

The slope reveals the rate and direction of change in the graph as x varies.

<pif m="" is="" positive="" increases="" in="" x="" result="" y.="">

If m is negative, increases in x lead to decreases in y.

<pthe regression="" equation="" is:="">

ŷ = –3.64x + 96.5

Where:

x = number of procrastination days

ŷ = anticipated grade

<pthus the="" slope="" is="" m="-3.64." this="" indicates:="">

A: With each additional procrastination day, the expected grade drops by 3.64 points.

</pthus></pthe></pif>
5 0
3 months ago
Read 2 more answers
Lily begins solving the equation 4(x – 1) – x = 3(x + 5) – 11. Her work is shown below. 4(x – 1) – x = 3(x + 5) – 11 4x – 4 – x
Zina [12379]

Finding a solution to an equation entails determining the value of x that renders the equation valid.

We must reverse the operations applied to x to isolate it.

4(x-1)-x = 3(x + 5)-11\\Distributing \; 4 \; and \; 3 \; in \; right \; and \; left \; side \; of \; the \; equation\\\\ 4x-4-x=3x+15-11\\Combine \; like \; terms\\\\3x-4=3x+4\\Subtract \; 3x \; on \; both \; sides\\\\3x-3x-4=3x-3x+4\\ Combine \; like \; terms\\\\-4=4

Final Note:

The resulting equation is false, indicating that there is NO solution. Graphically, both equations will be represented as parallel lines that do not intersect.

4 0
3 months ago
Read 2 more answers
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