Create a pattern for the rule a x 3 + 2

Answer:Part a)

Part b) When Jenny divides the square root of her favorite positive integer by , the result is an integer.

Step-by-step explanation:

Let

x-------> the favorite positive integer

Part a)

1) For

-----> the product results in an integer

thus

The number could potentially be Jenny's favorite positive integer

2) For

-----> the product results in an integer

thus

The number could potentially be Jenny's favorite positive integer

3) For

-----> the product results in an integer

thus

The number could potentially be Jenny's favorite positive integer

Part B)

1) For

-----> the outcome is an integer

2) For

-----> the outcome is an integer

3) For

-----> the outcome is an integer

Therefore

When Jenny divides the square root of her favorite positive integer by , she obtains an integer as a result.

A function and its inverse, when graphed, exhibit symmetry about the line y = x. Without viewing your graphs, I can't specify if g or h is the inverse. Identify the function that reflects f over the diagonal line y = x, which passes through the origin. 

5400000, since the 7 rounds the 8 up to 4.

Answer:

  (1/10)∛100 ≈ 0.4642

Step-by-step explanation:

For a cubic shape with volume V, the edge length is defined as...

  s = ∛V

and the surface area is given by...

  A = 6s² = 6V^(2/3)

The area-to-volume ratio is therefore...

  r1 = A/V = 6V^(2/3)/V = 6V^(-1/3)

When the volume V is increased by a factor of 10, the new area-to-volume ratio becomes...

  r2 = 6(10V)^(-1/3)

Consequently, the change factor for the ratio is...

  r2/r1 = (6(10V)^(-1/3))/(6V^(-1/3)) = 10^(-1/3) = (1/10)∛100

The change in surface area per unit volume results in a factor of (∛100)/10.

___

Example

For a cube with side length 2, the corresponding volume equals 2³ = 8, with a surface area of 6·2² = 24. The resulting area-to-volume ratio is 24/8 = 3.

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The area-to-volume ratio changed by a factor of (0.3∛100)/3 = (∛100)/10, as previously noted.

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X² + 7x - 8 = 0; product = -8 times 1 = -8; sum = 7; {-1, 8}; x² - 1x + 8x - 8 = 0; x(x - 1) + 8(x - 1) = 0; thus, x + 8 = 0 or x - 1 = 0, leading to x = -8.