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Cloud
11 days ago
7

The human eye is able to detect as little as 2.35 × 10–18 j of green light of wavelength 510 nm. Calculate the minimum number of

photons of green light that can be detected by the human eye. Physical constants can be found here.
Chemistry
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A person is standing on ice. He throws a snowball with a force of 4 N to the right, while the snowball pushes the person with a
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when two distinct forces are exerted in opposite directions, the resultant force is the subtraction of those forces
Therefore, 4 N - 4 N = 0 N
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Chlorine atoms from CFC molecules speed the breakdown of stratospheric O3 in a process that is affected by both homogeneous and
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3 months ago
The phosphorylation of glucose to glucose 6-phosphate Group of answer choices is so strongly exergonic that it does not require
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The process of converting glucose to glucose-6-phosphate is an endergonic reaction, which is coupled with the exergonic hydrolysis of ATP.

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2 months ago
Calculate the number of grams of carbon dioxide produced from complete combustion of one liter of octane by placing the conversi
Tems11 [2777]

Answer:

15.71g

Explanation:

The combustion equation that applies to hydrocarbons is

CxHy + (x+y/4) O2 = xCO2 + (y/2) H2O

In the case of octane, C8H18:

C8H18 + ( 8 + 18/4 ) O2 = 8CO2 + 9H2O

C8H18 + 50/4 O2 = 8CO2 + 9H2O

C8H18 + 25/2 O2 = 8CO2 + 9H2O

2C8H18 + 25 O2 = 16 CO2 + 18H2O (this is the balanced equation)

From this balanced reaction,

2 x 22.4 L of octane generates 16 [ 12 + (16 x 2)] of carbon dioxide

That means,

44.8 L of octane generates 704g of carbon dioxide

Thus, for 1L of octane, it produces 1 L x 704g/44.8 L = 15.71g of carbon dioxide

Consequently, 15.71g of carbon dioxide is produced from the complete combustion of 1 L of octane.

7 0
3 months ago
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