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zhenek
2 months ago
11

Automobiles are often implicated as contributors to global warming because they are a source of the greenhouse gas CO2. How many

pounds of CO2 would your car release in a year if it was driven 170. miles per week? Gasoline is a complex mixture of hydrocarbons. In your calculations, assume that gasoline is isooctane (molecular formula C8H18) and that it is burned completely to CO2 and H2O in the engine of your car. Also assume that the car averages 27.5 miles per gallon and that the density of isooctane is 0.692 g cm-3.
Chemistry
1 answer:
lions [2.9K]2 months ago
7 0

Answer:

Your vehicle would emit 5,747.82 pounds of CO_2 in a year if it were operated for 170 miles each week.

Explanation:

Car's fuel efficiency = 27.5 miles/gal

Weekly distance covered = 170 miles

Distance driven per day = \frac{170 miles}{7}=24.286 mile

Daily gasoline volume: V

\frac{24.286 mile}{27.5 miles/gal}=0.8831 gal=0.8831\times 3785.41 cm^3=3,342.96 cm^3

1 gal = 3785.41 mL = 3785.41 cm^3

Gasoline density = d= 0.692 g/cm^3

Daily gasoline mass = m

m=d\times V=0.692 g/cm^3\times 3,342.96 cm^3=2,313.33 g

2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O

Gasoline moles (isooctane):

=\frac{2,313.33 g}{114 g/mol}=20.292 mol

The chemical reaction shows that 2 moles of isooctane produce 16 moles of carbon dioxide gas. Therefore, 20.292 moles of isooctane will generate:

\frac{16}{2}\times 20.292 mol=162.340 mol carbon dioxide gas

The mass of 162.340 moles of carbon dioxide gas:

162.340 mol × 44 g/mol = 7,142.91 g

Daily carbon dioxide mass produced = 7,142.91 g

1 year = 365 days

Total carbon dioxide mass produced in 365 days:

= 365 × 7,142.91 g = 2,607,163.494 g

1 pound = 453.592 g

2,607,163.494 g=\frac{ 2,607,163.494}{453.592} pounds=5,747.82 pounds

Your car would emit 5,747.82 pounds of CO_2 if driven 170 miles weekly over a year.

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Answer: refer to the explanation

Explanation:

This question requires calculating mass. To determine the mass, we need values for two parameters, namely the specifications for the grade 70 tow chain and the mass per unit length given.

Assuming the mass per unit length is 3 kilograms per meter (kg/m) and the length of the grade 70 tow chain is 5 meters (m).

Thus, the formula used to compute the mass of the chain is as follows;

Mass of the chain = mass per unit length (kg/m) × length ---------------------------------------------------------------------------------------------------------------------(1).

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7 0
2 months ago
Compounds A and B are colorless gases obtained by combining sulfur with oxygen. Compound A results from combining 6.00 g of sulf
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Answer:

1.5

Explanation:

It is given that:

Compound A and B originate from Sulfur + Oxygen.

Compound A:

6g sulfur + 5.99g Oxygen

Compound B:

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By comparing the ratios:

Compound A:

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S/0 = 6.0g S / 5.99g O

Compound B:

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S / O = 8.60g S / 12.88g O

The mass ratio of A and that of B

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(6.0 g S / 5.99g O) × (12.88g O / 8.60g S)

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2 months ago
During which time interval does the substance exist as both a liquid and a solid
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what is the net ionic equation with its physical states? (NH4)2CO3(aq)+Ca(ClO4)2(aq)⟶CaCO3(s)+2NH4ClO4(aq)
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Explanation:

A double displacement reaction involves the exchange of ions. Chemicals that dissolve in water are marked with the symbol (aq), while those that do not dissolve and remain solid are shown with (s) after their formulas.

(NH_4)_2CO_3(aq)+Ca(ClO_4)_2(aq)\rightarrow CaCO_3(s)+2NH_4ClO_4(aq)

The ion-based representation of the equation is:

2NH_4^+(aq)+CO_3^{2-}(aq)+Ca^{2+}(aq)+2ClO_4^{-}(aq)\rightarrow CaCO_3(s)+2NH_4^{+}(aq)+2ClO_4^-(aq)

"Spectator ions" are the ions that do not participate in the chemical reaction, appearing on both sides of the equation in ionic form.

Ammonium and chlorate ions are present on both sides; thus, they do not factor into the net ionic equation.

Therefore, the net ionic equation is:

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Different wavelengths are involved.

Explanation:

When magnesium ignites with a bright white flame, it indicates that various wavelengths are related to the electron transitions occurring in the magnesium atom.

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Spectrum

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