Answer:- 64015 J
Solution: The calorimeter contains 4250 mL of water, which is at a temperature of 22.55 degrees Celsius.
The water's density is 1 gram per mL.
Thus, the mass of water =
= 4250 grams.
After introducing the hot copper bar, the final temperature of the water reaches 26.15 degrees Celsius.
Thus,
for the water = 26.15 - 22.55 = 3.60 degrees Celsius.
The specific heat capacity of water is 4.184
.
To determine the heat absorbed by the water, we can use the following formula:

where q represents heat energy, m refers to mass, and c indicates specific heat.
Now let's substitute the values into the equation to perform the calculations:

q = 64015 J
Therefore, the water absorbs 64015 J of heat.
Response: k = 23045 N/m
Clarification:
To determine the spring constant, one must consider the maximum elastic potential energy that the spring can withstand. The kinetic energy of the vehicle should equal at minimum the elastic potential energy of the spring when it is fully compressed. Hence, we express it as:
(1)
M: mass of the vehicle = 1050 kg
k: spring constant =?
v: car speed = 8 km/h
x: maximum spring compression = 1.5 cm = 0.015m
You need to resolve equation (1) for k. Beforehand, convert the speed v to meters per second:


The spring constant calculates to 23045 N/m
Answer: Copper is being oxidized and acts as a reducing agent. In contrast, silver is being reduced, functioning as the oxidizing agent.
Explanation:
An oxidation reaction involves the loss of electrons by an atom. Here, the oxidation state of the atom rises.

Conversely, a reduction reaction is characterized by an atom gaining electrons, resulting in a decrease in its oxidation state.

Oxidizing agents are those that facilitate the oxidation of another substance while themselves being reduced. These substances participate in reduction reactions.
Reducing agentsare defined as those that reduce other substances while undergoing oxidation themselves. They also take part in reduction reactions.
In the provided chemical reaction:

The associated half-reactions for the above process are:
Oxidation half reaction: 
Reduction half reaction: 
From the reactions outlined, copper is losing electrons. Consequently, it is oxidized and regarded as a reducing agent.
Silver is acquiring electrons, thus it is being reduced and viewed as an oxidizing agent.
Answer:

Explanation:
Charge of one electron = 
The formula for calculating charge is:

Given that: Charge = 


Total electrons, n = 
The ions involved are nitrate ions and potassium ions
ExplanationPotassium dichromate reacts with barium nitrate in a double-decomposition reaction that leads to the formation of barium dichromate and potassium nitrate. This process occurs due to the low solubility of barium dichromate, which tends to precipitate out of the solution shortly after it forms.Begin with the balanced chemical reaction for this interaction:

Recast the chemical equation into its ionic form; represent all soluble salts, indicated by state symbols (aq), as their individual ions while retaining the insoluble ones (s) intact.
and
are present on both sides of the reaction equally. Thus, these two ions do not participate in the net reaction and function as spectator ions.