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mojhsa
7 days ago
6

At a certain company, the annual winter party is always held on the second of Friday of December. What is the latest possible da

te for the party
Mathematics
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What is the domain of the square root function graphed below ?
AnnZ [12381]

The graph indicates that x never goes below 0. This means the point (-1,0) is not included in the graph. Therefore, D is the only valid option.

8 0
3 months ago
Read 2 more answers
Tricia is going to write Patterns A , B , and C using the rule add 15. The first number in each pattern is shown below . Use the
Inessa [12570]

Response:

The number 40 can be found in Pattern B. Additionally, following the rule, each sequence will expand.

Detailed breakdown:

Let’s build each sequence. Recall that the guideline is to "add 15" to generate each sequence starting from the provided initial number.

Pattern A.

5+20+35+50+65+80+95+110+125+140+155+170+185+200+215+...

Pattern B.

10+25+40+55+70+85+100+115+130+145+160+175+190+205+...

Pattern C.

15+30+45+60+75+90+115+130+145+160+175+190+205+...

You can see that the number 40 appears in Pattern B. Moreover, per the rule, each pattern will show an increase.

8 0
3 months ago
Select the correct answer from each drop-down menu.
AnnZ [12381]

Answer:

The answer is 7

Step-by-step explanation:

To find the base area of the triangular pyramid:

(base x height) / 2 = (4 x 3.5) / 2 = 7 in²

5 0
3 months ago
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Two factories — Factory A and Factory B — design batteries to be used in mobile phones. Factory A produces 60% of all batteries,
tester [12383]

Answer:

The likelihood of a battery being produced by Factory A and being defective is 0.012, which corresponds to 1.2%.

Step-by-step explanation:

We have two manufacturers of batteries for mobile phones: Factory A and Factory B. Factory A is responsible for 60% of the total battery production, while Factory B accounts for the remaining 40%.

Out of the batteries made by Factory A, 2% are found to be defective, whereas 4% of those from Factory B are defective.

Let P(A) denote the probability that a battery comes from Factory A, therefore P(A) = 0.60.

The probability that a battery originates from Factory B can be denoted as P(B) = 0.40.

Furthermore, define D as the event indicating that a battery is defective.

Thus, the probability of a defect given that a battery is from Factory A is P(D/A) = 0.02.

For Factory B, the probability of a defect given it is from there is P(D/B) = 0.04.

The probability for a battery being made at Factory A and also being defective can be calculated as follows:

Probability that Factory A produces batteries \times Probability that a battery from Factory A is defective

                       =  P(A) \times P(D/A)

                       =  0.60 \times 0.02 = 0.012  or  1.2%

Conclusively, the probability that a battery is both from Factory A and defective is 1.2%.

4 0
3 months ago
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