The visual representation is displayed in the following image.
For calculations, consider 100 grams of the compound:
ω(Cl) = 85.5% ÷ 100%.
ω(Cl) = 0.855; signifying the mass percentage of chlorine in the compound.
m(Cl) = 0.855 · 100 g.
m(Cl) = 85.5 g; this represents the mass of chlorine.
m(C) = 100 g - 85.5 g.
m(C) = 14.5 g; indicating the mass of carbon.
n(Cl) = m(Cl) ÷ M(Cl).
n(Cl) = 85.5 g ÷ 35.45 g/mol.
n(Cl) = 2.41 mol; this is the quantity of chlorine.
n(C) = 14.5 g ÷ 12 g/mol.
n(C) = 1.21 mol; this is the quantity of carbon.
n(Cl): n(C) = 2.41 mol: 1.21 mol = 2: 1.
The compound in question is identified as dichlorocarbene CCl₂.
Answer:
B, C
Explanation:
The Lewis dot structures that are valid are for B and C.
Regarding A;
The Lewis representation of carbon is correct. Each of the four dots symbolizes the four valence electrons.
However, the nitrogen with a single dot above, to the left, and below and a -3 charge isincorrect. For it to have a -3 charge, it must possess 8 Lewis dots (two on each side).
The nitrogen showing four dots (on top, right, bottom and left) is incorrect.
In B;
An oxygen having two dots positioned above and below with one dot on both sides is correct , as the 6 dots indicate oxygen's valence electrons.
In C;
A carbon shows two dots at each position and has a charge of +4. This is correct because the charge reflects that it has gained four electrons giving it 8 valence electrons.
In D;
An oxygen shows two dots above, to the left and below, with a charge of -2. This is incorrect as not all Lewis dots are present. Two are missing.
The solution to your inquiry is: c = a + b - d. In the chemical equation aA + bB → cC + dD, c may take any value from 1 to however many are needed for the equation to maintain its balance. For instance, if we consider c + d = a + b, we can express c as a + b - d. If we assign values a = 1; b = 3, and d = 2, then c equals 1 + 3 - 2, resulting in c = 2, and so forth.
1) To express 0.89% m/v, it equals 0.89 grams of NaCl per 100 ml of solution.
This corresponds to 8.9 grams of NaCl in 1000 ml of solution, or 8.9 grams in 1 liter.
2) Molarity is represented as M = moles of solute / liters of solution.
Thus, we need to determine the moles in 8.9 grams of NaCl.
3) The molar mass of NaCl is calculated as 23.0 g/mol + 35.5 g/mol = 58.5 g/mol.
4) Therefore, the number of moles of NaCl calculates as mass / molar mass = 8.9 g / 58.5 g/mol = 0.152 moles.
5) Consequently, M = 0.152 moles of NaCl / 1 liter of solution = 0.152 M.
Answer: 0.152 M
Response:
The mass percentage of a solution comprising 7.6 grams of sucrose and 83.4 grams of water equals 8.351 %.
Details:
Provided data:
Sucrose mass = 7.6 grams
Water mass = 83.4 grams
In this scenario, sucrose acts as the solute, while water is the solvent.
The calculation for mass percent of a solution is done using the following formula:
Mass percent = (Mass of Solute/Mass of Solution)(100)
As sucrose is the solute, the mass equals 7.6 grams.
The total mass of the solution, which includes both sucrose and water, comes out to:
Total mass = 7.6 grams + 83.4 grams = 91 grams
Therefore, applying the values gives mass percent = (7.6/91)(100) = 8.351 %.
