In a reaction, gaseous reactants form a liquid product. The heat absorbed by the surroundings is 1.1 MJ, and the work done on th

Answer:

K2X

Explanation:

The term valency refers to an element's capacity to combine with other elements. This property determines how an element is represented in a chemical compound's formula.

For magnesium and element X, represented as MgX, magnesium typically has a valency of +2 in its compounds. The absence of the +2 in the formula implies that element X must possess a -2 valency, resulting in a cancellation of the valencies.

Furthermore, potassium is classified as an alkaline metal in group 1 of the periodic table, leading to an expected valency of +1.

When forming a compound with element X, a valency exchange occurs. Since X has a -2 valency, the resulting formula of the compound formed by the exchange will be K2X.

Result:

94.7 %

Explanation:

The balanced reaction is:

2 S + 3 O₂ → 2 SO₃

The stoichiometric mole ratio is:

S: 2 moles

O₂: 3 moles

Moles are calculated as mass divided by molar mass:

n = w / m

where n = moles, w = mass, m = molar mass.

Given:

For sulfur: w = 6.0 g, molar mass = 32 g/mol, so n = 6 / 32 = 0.1871 mol

For oxygen: w = 5.0 g, molar mass = 32 g/mol, thus n = 5 / 32 = 0.15625 mol

Comparing to stoichiometric ratios, sulfur is in excess, so oxygen is the limiting reagent, controlling product formation.

Using proportions:

3 mol O₂ produce 2 mol SO₃, so 1 mol O₂ yields 2/3 mol SO₃.

Therefore, 0.15625 mol O₂ yields (2/3) × 0.15625 = 0.1042 mol SO₃.

Mass of SO₃ produced = n × molar mass = 0.1042 mol × 80 g/mol = 8.340 g

The percentage yield is actual yield divided by theoretical yield times 100:

Percent yield = (7.9 g / 8.340 g) × 100 = 94.7 %

The molar masses for H2S and NH3 are 34 and 17 g/mol, respectively. The appropriate equation to represent this is,
                                  Rate A/Rate B = √(molar mass B/molar mass A)
Substituting values,
                               x/77 = √(17 /34 )
                                 x = 54.4
This means NH3 will take 54.4 seconds to escape through the container. 

Explanation:

Here’s the provided information:

Density of gasoline = 0.77 g/ml

Volume of gasoline = 35 L = 35000 ml (since 1 L = 1000 ml)

Density of a substance is defined as its mass divided by its volume.

Mathematically, Density = .

<pthus we="" can="" determine="" the="" mass="" of="" specified="" gasoline="" as="" follows:="">

Density =

0.77 g/ml =

mass = 26950 g.

It is further noted that burning 1 g of gasoline generates 45.0 kJ of energy.

<pconsequently the="" energy="" produced="" by="" burning="" g="" of="" gasoline="" will="" be="" calculated="" as="" follows:="">

= 1212750 kJ.

<pthus we="" conclude="" that="">the energy released by combusting 35 L of gasoline amounts to 1212750 kJ.

</pthus></pconsequently></pthus>

Mass of vaporized triethylamine: 2.606 g

Further explanation

Given

0.5 L of triethylamine

P = 18.5 psi

T = 25 °C

Required

the mass of vaporized triethylamine

Solution

Conversion:

P 18.5 psi = 1.26 atm

T = 25 + 273 = 298 K

Using the ideal gas law:

PV=nRT

n = PV/RT

Insert the values:

n = (1.26 atm x 0.5 L) /(0.08205 x 298)

n = 0.0258

With the molecular weight of triethylamine being 101 g/mol, we find:

mass of triethylamine:

= n x MW

= 0.0258 x 101 g/mol

= 2.606 g