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kow
4 months ago
11

In a reaction, gaseous reactants form a liquid product. The heat absorbed by the surroundings is 1.1 MJ, and the work done on th

e system is 13.2 kcal. Calculate ΔE (in kJ). Be sure to include the correct sign (+/-). Enter to 0 decimal places.
Chemistry
1 answer:
alisha [2.9K]4 months ago
4 0

Answer: \Delta E is 1155 kJ

Explanation:

The first law of thermodynamics states:

\Delta E=q+w

\Delta E=Change in internal energy

q represents the heat exchanged, either absorbed or released

w pertains to the work done by or on the system

w = work performed on the system=-P\Delta V  {Since work is done on the system, it is positive because the final volume is less than the initial volume}

w =13.2kcal=55.2kJ   (1kcal=4.184 kJ)

q amounts to +1.1 MJ = 1100 kJ  (1MJ=1000kJ)   {The system absorbs heat, making this value positive}

\Delta E=1100kJ+(55.2)kJ=1155kJ

Consequently, \Delta E is 1155 kJ

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