Answer:
25.2 kJ
Explanation:
The full question can be found in the image linked to this response.
It's important to highlight that the heat absorbed by the 2.00 L of water for increasing its temperature from the beginning to the end comes solely from the burning of benzoic acid, as there are no heat transfers to the container or the surroundings.
To find the heat released from benzoic acid combustion, we simply measure the heat needed to warm the water.
Q = mCΔT
To find the mass of the water,
Density = (mass)/(volume)
Mass = Density × volume
Density = 1 g/mL
Volume = 2.00 L = 2000 mL
Mass = 1 × 2000 = 2000 g
C = specific heat of water = 4.2 J/g.°C
ΔT = (final temperature) - (Initial temperature)
<pAccording to the graph,
Final water temperature = 25°C
Initial water temperature = 22°C
ΔT = 25 - 22 = 3°C
Q = (2000×4.2×3) = 25,200 J = 25.2 kJ
Hope this Helps!!!
Answer:
Explanation:
We have:
V₁ = 18.5 L
T₁ = 18.5° C = 273 + 18.5 = 291.5 K
V₂ = 19.8 L
T₂ =?
Pressure remains constant
Applying the ideal gas law
Answer;
Considering the types of bonds being created and severed in the transition state, the stability of this temporary structure is comparatively high.
Explanation;
- The reaction can be expressed as follows; NO(g)+F2(g)→NOF(g)+F(g)
- All chemical reactions, including exothermic ones, require activation energy to initiate. The activation energy is the least amount of energy needed for the reactants to come together, overcome opposing forces, and begin breaking bonds.
- When molecules encounter each other, their kinetic energy may be sufficient to stretch, bend, and eventually break bonds, resulting in chemical reactions.
The result is 0.14303691.
Carbon-13 (¹³C) is a stable isotope of carbon with a mass number of 13, composed of six protons and seven neutrons.
Isotopes are elements that share the same atomic number but have different mass numbers, meaning they have a varying number of neutrons.
ω(¹³C) = 1.10% ÷ 100%.
ω(¹³C) = 0.0110; this indicates the natural abundance of carbon-13.
m(¹³C) = 13.003355; the atomic mass assigned to carbon-13.
ω(¹³C) · m(¹³C) = 0.0110 · 13.003355.
ω(¹³C) · m(¹³C) = 0.14303691.
Answer:
Calcium's atomic radius is roughly 175 pm.
Explanation:
We know that magnesium has an atomic radius of 150 pm.
The atomic radius of strontium measures 200 pm.
Since calcium's position is between magnesium and strontium in group 2 of the periodic table, its atomic radius should be roughly averaged between magnesium's and strontium's atomic radii because atomic radius is not constant.
Thus;
Calcium's atomic radius is approximately calculated as follows;
The average atomic radius is (200 + 150)/2 = 175 pm.
